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melisa1 [442]
3 years ago
7

Please answer this question now in two minutes

Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0

Answer:

y=x+5

Step-by-step explanation:

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Which expression is not equivalent to 3 times a times r
Paladinen [302]

The last one

Step-by-step explanation:

The last one is dividing.

5 0
3 years ago
Read 2 more answers
What is the equatipn of the linear graph?<br> (-4, 6).<br> (1, -9)
dusya [7]

Answer:

y = -3x - 6

Step-by-step explanation:

first, find the slope

(-4, 6)

(1, -9)

remember the equation for the slope

\frac{y_{2}-y_{1}}{x_{2} - x_{1}} }

insert given points

x_{1} = -4\\y_{1} = 6\\\\x_{2} = 1\\y_{2} = -9

((-9) - (6)) / ((1) - (-4))

simplify

( -9 - 6) / (1 + 4)

= -15/ 5

= -3

now insert it into the equation of the line

remember, the equation of the line is

y = mx + b

where "m" is the slope

and "b" is the y-intercept

to find "b", you just have to plug in a point that is found on the line

we know that (-4, 6) and (1. -9) is found on the line, so let's just use (-4, 6) for this problem

y = mx + b

substitute in the slope of this line

y = -3x + b

now substitute in the given points

6 = -3 * -4 + b

and solve it like any algebra problem, by inverse operations and simplifying

6 = 12 + b

-12      -12

-6 = b

so the equation of the line is

y = -3x -6

3 0
3 years ago
What should you do to both sides of the inequality in order to solve x + (-2) &gt; 3?
lilavasa [31]

x+(-2) >3

open the bracket

x-2>3

collect the like terms by taking 2 to the other side

x>3+2

x>6

3 0
2 years ago
I need help with this(explain). what is the value of the expression 2x^2 + 3xy - 4y^2 when x=2 and y= -4 ​
Strike441 [17]

Answer: The answer is -80

Step-by-step explanation:

2(2^2)+(3)(2)(−4)−4(−4)^2

2(2^2)+(3)(2)(−4)−4(−4)^2

=−80

4 0
3 years ago
A bug is moving back and forth on a straight path. The velocity of the bug is given by vt=t2-3t. Find the average acceleration o
g100num [7]

Answer:

2 unit/time²

Step-by-step explanation:

Given the equation:

v(t) =t^2-3t

At interval ; 1, 4

V(1) = 1^2 - 3(1)

V(1) = 1 - 3

V(1) = - 2

At t = 4

V(4) = 4^2 - 3(4)

V(4) = 16 - 12

V(4) = 4

Average acceleration : (final - Initial Velocity) / change in time

Average acceleration = (4 - (-2)) ÷ (4 - 1)

Average acceleration = (4 + 2) / 3

Average acceleration = 6 /3

Average acceleration = 2

3 0
3 years ago
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