The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
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Answer:
1
0
(
3
+
4
)
Step-by-step explanation:
<u>(Note: this answer is assuming that the equation has to be put in slope-intercept format.)</u>
Answer:

Step-by-step explanation:
1) Let's use the point-slope formula to determine what the answer would be. To do that though, we would need two things: the slope and a point that the equation would cross through. We already have the point it would cross through, (-3,-4), based on the given information. So, in the next step, let's find the slope.
2) We know that the slope has to be parallel to the given line,
. Remember that slopes that are parallel have the same slope - so, let's simply take the slope from the given equation. Since it's already in slope-intercept form, we know that the slope then must be
.
3) Finally, let's put the slope we found and the x and y values from (-3, -4) into the point-slope formula and solve:

Therefore,
is our answer. If you have any questions, please do not hesitate to ask!
Answer:
the correct answer is B. 135 cu. units