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Aleksandr-060686 [28]
3 years ago
9

Solve 4y^2-16y+16=0.

Mathematics
2 answers:
Snezhnost [94]3 years ago
7 0

Answer:

y=2

Step-by-step explanation:

1) factor the equation

2) set factors equal to 0

madreJ [45]3 years ago
6 0

Answer: y=2

Step-by-step explanation:

4y^2-16y+16=0                 To "solve" means to find the value of x for which this equation is true.

y^2 -4y + 4 = 0               [divide by 4; this is the same equation]

 (y-2)(y-2) = 0               [You may factor or use the quadratic equation]

   y=2 and y=2     [the same answer]

Check:

   Does  (2)2 - 4(2) + 4 = 0    ?

             4   -   8    + 4  = 0   ?

                   0    =   0   ?  yes

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