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sineoko [7]
3 years ago
14

What is the solution for the system of equations?

Mathematics
1 answer:
taurus [48]3 years ago
7 0
Rearrange the first equation2x + y = 20take away 2x from both sidesy = 20 - 2x substitute this y value into the second equation6x - 5(20 - 2x) = 126x -100 +10x = 12add 100 to both sides6x + 10x = 11216x = 112divide both sides by 16 x = 7Substitute this x value into the first equation to get y.2(7) + y = 2014 + y = 20take away 14 from both sidesy = 6
So, y = 6 and x = 7
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3. Given ABCD ≅ FGHJ and mC = 9x - 7, mH = 5x + 13, find the value of x and the measures of angle C and angle H. Show all work
Bas_tet [7]
Since congruence and similarity for polygons is posted in a specific order, we know that angle A=angle F, side A=side F, die B=side G, and so on. Therefore, we have that angle C=angle H = 9x-7=5x+13. Subtracting 5x from both sides to separate the x using the subtraction property of equality, we get 4x-7=13. Next, we can add 7 to both sides to get 4x=20, and divide both sides by 4 to isolate the x and get x=5. Plugging that into angle C or angle H, we get that 9x-7=9*5-7=45-7=38=5*5+13.

Feel free to ask further questions!
5 0
3 years ago
a bank charges a simple interest of 3.5% on a loan of $5000 to be paid back over a period of 3 years. How much will the borrower
user100 [1]

Answer: The monthly payments for a $5,000 loan would $146.51.

Step-by-step explanation: How it looks in the TVM Solver formula:

N = 36 ( 3 (years) x 12 (monthly payments) )

I% = 3.5%

PV = $5,000

PMT = 146.51 (or 146.08 if you choose BEGIN)

FV = 0

P/Y = 12 (months)

C/Y = (12 (months)

PMT: <u>END</u> | BEGIN

6 0
3 years ago
6⁄10 _______ 9⁄12 A. &gt; B. ≤ C. = D.
Ivanshal [37]
6/10 is equal to 0.60
9/12 is equal to 0.75
your answer is not above for D but if D is < then that would be the correct answer :)
7 0
3 years ago
Read 2 more answers
If 45% of a number g is 225 what is 74% of g
Gelneren [198K]
370
You first have to divide 225 by 45 and then multiply by 74
5 0
3 years ago
What's the domain and range for (×+4)-1
Sonja [21]
\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad&#10;&#10;\cfrac{1}{a^{ n}}\implies a^{-{ n}}\\&#10;---------------\\&#10;thus\\&#10;(x+4)^{-1}\implies \cfrac{1}{x+4}&#10;\\\\&#10;
\bf if\qquad \cfrac{1}{0} \implies undefined

so.. what value of "x" makes x+4 to 0?

the domain will be, all real numbers, except that value

about the range, "y" will take, whateve "x" can provide.. in this case... I think is all real numbers, except 0, because, if you give a few big values to "x", the fraction will simply have a bigger and bigger denominator, making the fraction smaller and smaller, ever approaching 0, but never getting there
7 0
3 years ago
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