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Basile [38]
3 years ago
13

Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credi

t:
x^2 + 4x + y^2 − 6y = −4
Mathematics
1 answer:
Nitella [24]3 years ago
5 0

Answer:

Circle with center at (-2,3) and radius r=3.

Step-by-step explanation:

Rewrite equation in standard form.

(x-a)^2+(y-b)^2=r^2

(x-(-2))^2+(y-3)^2=3^2

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3) A tour trolley covers a distance of 8.5 miles in of an hour.
sp2606 [1]

Answer:

a) Ans: 8.5 miles per hour

b) Ans: 46.75 miles

Step-by-step explanation:

a) Speed = Distance/Time

8.5/1h = 8.5 miles per hour

b) Distance = Speed x Time

8.5 miles per hour x 5.5h = 46.75 miles

5 0
3 years ago
The diagonals of a quadrilateral bisect at right angles. What type of quadrilateral is this?
arsen [322]

square

Step-by-step explanation:

8 0
3 years ago
If the diameter of the circle is above 20mm what is the area
Phoenix [80]

Answer:

The area would be 314.16 mm squared

7 0
3 years ago
The weight of a bull clad is 388 kilograms. If it’s weight increases at a rate of 1 2/5 kilograms per day how long it will take
Alex73 [517]

Answer:

It will take  <u><em>80 days</em></u>  for the bull calf to reach a weight of 500 kilograms.

Step-by-step explanation:

Given:

The weight of a bull calf is 388 kilograms.

Now, to find the weight of bull calf of how long it will take to reach a weight of 500 kilograms, if it’s weight increases at a rate of 1 2/5 kilograms per day.

Required weight which to be increased = 500 - 388 = 112 kilograms.

Rate of weight increase = 1\frac{2}{5}=\frac{7}{5}

                                        = 1.4\ kilograms.

Thus, the time required = \frac{required\ weight}{rate\ of\ weight}

                                        = \frac{112}{1.4}

                                        = 80.

<em>The time required   =    80 days</em>.

Therefore, it will take 80 days for the bull calf to reach a weight of 500 kilograms.

5 0
3 years ago
An ant crawls at a rate of 216 ft per minute. At this rate, how long does it take the ant to crawl a distance of 515 ft? Enter y
quester [9]
216 ft per minute or 3.6 ft per second 
515 divided by 216 is 2.38 
it takes 2.38 minutes for the specified ant to crawl 515 feet 

5 0
4 years ago
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