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3 years ago

I have a test tmrw pls help

Mathematics

2 answers:

s2008m [1.1K]3 years ago

7 0

So first you would have to find the slope using the two points and the equation: y2-y1/x2-x1, which in this case means you take 6+4/3+1, which would be a slope of 10/4 or 5/2, or 2.5. Using this, we can take a point, use point slope form, and rearrange it. So:

y-6=2.5(x-3)

y-6=2.5x-7.5

-2.5x+y=1.5

Dvinal [7]3 years ago

4 0

The answer is 5x -2y = 3

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Need help with this asap

valentina_108 [34]

Answer: the first one is exponential and the second one is function

6 0

2 years ago

A test has 20 question if peter gets 80% correct, how many question did peter miss

AlexFokin [52]

Answer:

16 questions right = 80%

So Peter missed 4 questions.

Hope this helps.

:-)

6 0

3 years ago

Read 2 more answers

There is a rectangular prism that can fit 28 cubes with edge lengths of 1/2 inch each. What is the volume of this rectangular pr

siniylev [52]

Answer:

3.5 inch^3

Step-by-step explanation:

Volume of cube: V = s^2,

where V = volume, and s = length of side or edge.

The volume of the prism is the same as the volume of 28 cubes with edge length of 1/2 inch. To find the volume of the prism, find the volume of one cube and multiply by 28.

volume of prism = 28 * volume of cube

volume of prism = 28 * (1/2 inch)^3

volume of prism = 28 * 1/8 inch^3

volume of prism = 3.5 inch^3

3 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

A number cube has faces numbered 1 through 6, and a coin has two sides, "heads" and "tails". The

Mama L [17]

Answer:

The required probability is $\dfrac{1}{12}$ .

Step-by-step explanation:

Let A be the event of rolling the number cube.

Let B be the event of tossing the coin.

Total number of possibilities of rolling the number cube and tossing the coin are 12 here.

$\{(1,H),(2,H),(3,H),(4,H),(5,H),(6,H),(1,T),(2,T),(3,T),(4,T),(5,T),(6,T)\}$

where H means Head on toss of coin and T means Tails on toss of coin.

Formula for probability of an event E is:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Here, we have to find the probability of event 'E' i.e. getting a 6 on number cube and heads on coin.

Number of favorable cases are 1 and total cases are 12.

$\Rightarrow P(E) = \dfrac{1}{12}$

6 0

2 years ago