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romanna [79]
3 years ago
8

Which equation can be used to find the nth term of the sequence, an?

Mathematics
2 answers:
Nana76 [90]3 years ago
6 0

Answer:

The answer is D i.e an=34-4n

Aloiza [94]3 years ago
6 0

Answer:

an=34−4n

Step-by-step explanation:

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What is 4 and 1/4 -1 and 3/4
Sergio039 [100]

Answer:

youre answer is:

2.5

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8 0
3 years ago
I’m so confused I don’t know how to subtract fractions. What is 2+2-1 2/3
Alexxandr [17]

Answer:

its 7/3 or you could put 2 1/3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
the height of a triangle is 9m less than its base. the area of the triangle is 56 m^2 find the length of the base (SHOW STEPS)
Veronika [31]
Hey there :)

We know the area formula of a triangle
\frac{1}{2} (base)(height)

We are given:
The area = 56 m²
The base = let p represent this
The height = 9 m less than the base = p - 9

Apply the formula
56 = \frac{1}{2} × ( p ) × ( p - 9 )
56 = \frac{1}{2} × ( p² - 9p )

Divide \frac{1}{2} on both sides
56 ÷ \frac{1}{2} = p² - 9p
112 = p² - 9p

Bring 112 to the other side and equate equation to 0
p² - 9p - 112

Factorise { Sum = -9 , Product = - 112 , therefore suitable factors = - 16 × 7 )
( p - 16 )( p + 7 ) = 0
     ↓          ↓
 p = 16    p = - 7  ←  Reject p = - 7 since length cannot be negative

So, the length  of the base is 16 m

Check:
56 m² = \frac{1}{2} × 16 × ( 16 - 9 )
56 m² = 8 × 7
56 m² = 56 m²
7 0
3 years ago
Consider the graph of the line y = .5x- 4 and the point
Katena32 [7]

Answer:

slope of parallel line and perpendicular line are 5 and -1/5 espectively

equation of parallel and perpendicular line are y = 5x + 22 y= \frac{-1}{5} x+\frac{6}{5} respectively

Step-by-step explanation:

y = 5x - 4 is in the form

y = mx + c

where m is the slope of the line and c is the y intercept of thr line

therefore slope of the line = 5 and y intercept = -4

when an another line is parallel to the given line then the slope of both the lines are equal

therefore the slope the parallel line = 5

equation of a line passing through a given point (x_{1} ,y_{1}) with slope m is given by y-y_{1} = m(x-x_{1} )

given (x_{1} ,y_{1})= (-4,2)

therefore equation of line y-2 = 5(x+4)

therefore y = 2+ 5x+20

y = 5x + 22is the eqaution of required line.

when two lines are perpendiculer then

m_{1} m_{2}=-1

where m_{1} and m_{2} are slope of the lines therefore

m×5=-1

therefore m= \frac{-1}{5}

therefore eqaution of line passing through (-4,2) and with slope m= \frac{-1}{5} is given by y - 2= \frac{-1}{5} (x+4)

y= \frac{-1}{5} x+\frac{6}{5}

3 0
3 years ago
Formula of sec theta​
katovenus [111]

Answer:

sec(theta)=1/cos(theta)

Step-by-step explanation:

sec(theta)=1/cos(theta)

6 0
2 years ago
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