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3 years ago

Graph the linear equation. Find three points that solve the equation, then plot on the graph.

Mathematics

2 answers:

LenaWriter [7]3 years ago

5 0

Answer:

Three points are: (-2,0) , (0,1) , (2,2)

Step-by-step explanation:

Given: -x+2y=2

Put x=0 into -x+2y=2

2y=2

y=1

Point: (0,1)

Put x=-2 into -x+2y=2

2+2y=2

y=0

Point: (-2,0)

Put x=2 into -x+2y=2

-2+2y=2

y=2

Point: (2,2)

Three points are: (-2,0) , (0,1) , (2,2)

Plot the points on graph and join them.

Please see the attachment for graph.

marusya05 [52]3 years ago

5 0

-x+2y=2
2y=x+2
y=1/2(x+2)
y=1/2*x+1

find first x and y intercept
x=0 y=1
y=0,x=-2

m=1/2
three points are(0,1),(1,3/2),(2,2),(3,5/2)
u can take some negative values of x also like
x=-1,y=1/2,(-2,0)

U see the slope is 1/2 means rate of change of values in x and y's are 1/2 constant so u can graph like that.

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Pls answer asap!! will mark brainliest giving 50 points ty ily <3

malfutka [58]

Answer:

Step-by-step explanation:

Keep the order of opperations in mind when doing this (PEMDAS). First, solve what is inside the parentheses (6-1). Then, solve the exponent and the multiplication (6² and 5×5). Finally, finish adding and subtracting to get the answer.

4 0

3 years ago

Read 2 more answers

I’m supposed to find the slope intercept form. The x intercept is (2,0) and the y intercept is (0,6). I keep getting 6/2. But, t

Lilit [14]

$\bf \stackrel{x-intercept}{(\stackrel{x_1}{2}~,~\stackrel{y_1}{0})}\qquad \stackrel{y-intercept}{(\stackrel{x_2}{0}~,~\stackrel{y_2}{6})} \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-0}{0-2}\implies \cfrac{6}{-2}\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=-3(x-2)\implies y=-3x+6$

5 0

2 years ago

Q4: Write the equation in slope-intercept form of the line that is perpendicular to

forsale [732]

Answer:

5y = x + 11

Step-by-step explanation:

Given parameters:

Equation of the line ;

y = -5x + 1

Coordinates = (2, -1)

Find the equation of a line perpendicular;

Solution:

A line perpendicular to y = -5x + 1 will have slope that is a negative inverse of the given one.

Equation of a straight line is expressed as;

y = mx + c

y and x are the coordinates

m is the slope

c is the y-intercept

So, the slope of the new line perpendicular is $\frac{1}{5}$ ;

Now let us find the y-intercept of the new line;

x = -1 and y = 2

2 = $\frac{1}{5}$ x (-1) + c

c = 2 + $\frac{1}{5}$ = $\frac{11}{5}$

The equation of the new line is;

y = $\frac{1}{5}$ x + $\frac{11}{5}$

or multiply through by 5;

5y = x + 11

5 0

2 years ago

Please help... I really need this.

valentinak56 [21]

Answer:

$\frac{4x^3-3x^2+5x+6}{x+6}=4x^2-27x+167-\frac{996}{x+6}$

Step-by-step explanation:

The division problem given to us is $(4x^3-3x^2+5x+6)\div (x+6)$ .

To perform the synthetic division, we write out the coefficient of the polynomial. We set the linear factor to zero and solve for x, this becomes our divisor. That is $x+6=0\implies x=-6$ .