Let’s come back to the equation of SPEED OF AN ECHO
SPEED =2XDISTANCE/ TIME
So 337*7/2=1179.5 nearest meter =1800 m away
Hope you will get it right
Answer: An oxbow lake forms after there has been deposition of sediment, by the new cutoff channel flowing adjacent to it, at the entrances of the abandoned bend; this seals the bend off from the rest of the river.
Answer:
Rachel(2.5,0)
ball(6.5,4.7)
b.R=10.15m/s, 27.57deg
Explanation:
The reference angle of Rachel is 0
resolving rachel's speed to the horizontal, we have
Ux=2.5cos0
Ux=2.5m/s
resolving rachel's speed to the vertical we have,
Uy=2.5sin0
Uy=0
for the ball
resolving the speed to its horizontal component
Ux=8cos36
Ux=6.5m/s
Uy=8sin36
Uy=4.7m/s
Rachel(2.5,0)
ball(6.5,4.7)
To get the resultant of their speed
Add the horizontal speed of rachel to that of the ball to get the total horizontal speed
Add the vertical speed of rachel and the ball to get the total vertical speed component
TUx=2.5+6.5=9M/S
TUy=0+4.7=4.7m/s
R=
R=
R=
R=10.15m/s
the direction
tan
=TUy/TUx
tan
=4.7/9
=tan^-1(0.522)
=27.57deg
Answer: gold ,oxygen magnesium
Explanation:
we cannot conclude air because it is mixture of gases , blood is also mixture of plasma , thrombocyte ; co2 is a compound ,