Ask question

Ask question

All categories

3 years ago

7

Which ordered pair is the vertex of y=|x+5|-1

1 answer:

nataly862011 [7]3 years ago

3 0

We can tell that this absolute value function opens up, so the vertex will be at the x value where the output is the lowest. The lowest you can make |x+5| go is 0, because everything else will be a positive number is greater. The one x value that does that is -5. Plug in -5, and you will get |-5+5|-1=-1. So, the ordered pair for the vertex will be (-5,-1)

You might be interested in

Can someone give me the answer for this? __ (5 + 4) = 2 * 5 + 2 * 4

wariber [46]

Answer:

the answer is two man..ya know

5 0

2 years ago

Read 2 more answers

The surface area of a sphere with a diameter of 12 units is:

svetlana [45]

Answer:

Surface area of sphere = 4πr²

r = radius

radius = diameter /2

= 12/2

= 6units

Surface area = 4π×6²

= 144π

= 452.4 square units

Hope this helps.

4 0

3 years ago

What is the answer to this question

astra-53 [7]

Answer: I think the answer is B

Step-by-step explanation:

8 0

3 years ago

Graphing Exponential Function in Exercise ,sketch the graph of the function.See example 3 and 4.

Vlad [161]

Answer:

The attached image shows the graph for the given function.

Step-by-step explanation:

We are given the following function in the question:

$y(x) = 2^{x-1}$

We have to graph the given function.

Properties of the given function are:

It is an exponential function of the form $y(x) = a^{x + b}$
Here, a = 2, b = -1
The y-intercept of the given function is (0,0.5)
There is no x-intercept.
The domain of the given function is all real numbers.
The range of given function is $(0,\infty)$

The attached image shows the graph for the given function.

5 0

3 years ago

In quadratic formula

lorasvet [3.4K]

x² - x - 12 = 0

$x = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a}$

a = 1, b = -1, c = -12

$x = \dfrac{1 \pm \sqrt{(-1)^{2} - 4(1)(-12)}}{2(1)}$

x = 4 or -3

Answer: 4 or -3

4 0

3 years ago