A coin is dropped from a height of 188 meters. Neglecting air resistance, how much time (in seconds) was the coin in the air?
1 answer:
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Answer:
1.00 m/s^2
Explanation:
The problem can be solved by using Newton's second law:
where
F is the net force acting on an object
m is the mass of the object
a is its acceleration
In this problem, F=35 N (the force applied by Amber) and
is the mass of the wagon + the brother, so the acceleration of the wagon and the brother is
Answer:
The separation distance between the two charges must be 82704.2925 m
Explanation:
Given:
Two negative charges that are both q = -3.8 C
Force of 19 N
Question: How far apart are the two charges, s = ?
First, you need to get the electrostatic force of this two negative charges:
Here
k = electric constant of the medium = 9x10⁹N m²/C²
Substituting values: