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Rashid [163]
3 years ago
6

A 4.00-kg model rocket is launched, expelling 64.0 g of burned fuel from its exhaust at a speed of 675 m/s. What is the velocity

of the rocket after the fuel has burned
Physics
1 answer:
olga_2 [115]3 years ago
3 0

Answer:

The velocity of the rocket is 7.8 m/s

Explanation:

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The right half will be a new bar magnet of 2cm with north pole on the right side and south pole on teh left.
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Name at least 4 things our atmosphere does for us
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8 0
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_________ acceleration occurs when an object speeds up.
Angelina_Jolie [31]

Positive acceleration occurs when an object speeds up.

Explanation:

Acceleration is the rate of change in velocity per unit time:

a=\frac{\Delta v}{\Delta t}

where \Delta v is the change in velocity while \Delta t is the time interval. From the formula, we can understand that when \Delta v is positive, so when the object is speeding up, the acceleration is positive; on the contrary, when \Delta v is negative (so, when the object is slowing down), the acceleration is negative.

7 0
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Give two examples of situations or application where electronic circuits are used
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A battery running to a transistor to regulate voltage to then power an LED lightbulb.
7 0
2 years ago
A 143-g baseball is flying through the air with a speed of 180 km/hr just after it is hit by a bat. If its velocity is at an ang
Svetllana [295]

To solve the problem it is necessary to apply the concepts related to the conservation of linear Moment, that is to say

P=mv

Where,

m = Mass

v = Velocity

P = Linear momentum

For the given data we have to:

v_1 = 180\frac{km}{h}(\frac{1h}{3600s})(\frac{1000m}{1km})

v_1 = 50m/s

The components of this force would be given by,

v_z = 50*sin37 = 30.09m/s

v_{x,y} = 50*cos37=39.93m/s \rightarrwAccording to the definition given at the end of the problem, this component corresponds to that expressed for x and y.

Applying the previous equation we have,

\vec{P} = m(39.93cos\theta \hat{i}+39.93sin\theta \hat{j}-30.09\hat{k})

<em>Note: The component at this direction must also decomposed</em>

The mass is 143g=0.143kg, then:

\vec{P} = (0.143)(39.93cos(22)\hat{i}+39.93sin(22) \hat{j}-30.09\hat{k})

Therefore the final vector is:

\vec{P} = 5.29\hat{i}+2.138\hat{j}-4.29\hat{k})

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3 years ago
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