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Nat2105 [25]
3 years ago
11

PLZ HELP!!!!

Physics
2 answers:
Nitella [24]3 years ago
6 0
B, the pitch is higher because the sound waves are compressed by the vehicle as it moves towards the observer.
noname [10]3 years ago
4 0
I believe the answer would be B) ...... sorry if i'm wrong
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I feel like I’ve been on this physics exam forever… please help . NO LINKS.
sesenic [268]

Explanation:

my guess is A

emission spectrum of a chemical element or chemical compound is the spectrum of frequencies of electromagnetic radiation emitted due to an atom or molecule making a transition from a high energy state to a lower energy state.

4 0
3 years ago
The electric potential at a point equidistant from two particles that have charges +Q and –Q is larger than zero. a. smaller tha
Marizza181 [45]

Answer:

idk, idk cause i'm steppin on my toes and i can't stop i make flips ou of my flops

Explanation:

8 0
4 years ago
You throw a rock straight up from the edge of a cliff. It leaves your hand at time t = 0 moving at 13.0 m/s. Air resistance can
Zarrin [17]

Answer:

0.36s, 2.3s

Explanation:

Let gravitational acceleration g = 9.81 m/s2. And let the throwing point as the ground 0 for the upward motion. The equation of motion for the rock leaving your hand can be written as the following:

s = v_0t + gt^2/2

where s = 4 m is the position at 4m above your hand. v_0 = 13 m/s is the initial speed of the rock when it leaves your hand. g = -9.81m/s2 is the deceleration because it's in the downward direction. And t it the time(s) it take to get to 4m, which we are looking for

4 = 13t - 9.81t^2/2

4.905 t^2 - 13t + 4 = 0

t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{13\pm \sqrt{(-13)^2 - 4*(4.905)*(4)}}{2*(4.905)}

t= \frac{13\pm9.51}{9.81}

t = 2.3 or t = 0.36

7 0
4 years ago
Read 2 more answers
A box sliding on a horizontal frictionless surface runs into a fixed spring, compressing it a distance x1 from its relaxed posit
inn [45]

Answer:twice of initial value

Explanation:

Given

spring compresses x_1 distance for some initial speed

Suppose v is the initial speed and k be the spring constant

Applying conservation of energy

kinetic energy converted into spring Elastic potential energy

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx_1^2----1

When speed doubles

\dfrac{1}{2}m(2v)^2=\dfrac{1}{2}kx_2^2----2

divide 1 and 2

\dfrac{1}{4}=\dfrac{x_1^2}{x_2^2}

x_2=2x_1

Therefore spring compresses twice the initial value

   

7 0
3 years ago
8x^3/27y^8×9y^3/12x^2
konstantin123 [22]
2x/ 9y^5  this is your answer

4 0
4 years ago
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