Answer:
Yes, by AA~
Step-by-step explanation:
You can tell by the two angles with a measure of 77.1 degrees.
Answer:
(3/2)π units²
Step-by-step explanation:
Hello, Katherine,
Your central angle, Ф, is 60°.
To find the area of this sector, we recognize that its central angle, 60°, is (1/6) of the area of the entire circle:
A of sector = (1/6)(π)(3 units)² = 9π units²
-------------- = (3/2)π units²
6
Note: (60 degrees) / (360 degrees) = (1/6)
This is the answer to your question
Answer:
The half-life of the substance is about 288 days.
Step-by-step explanation:
The exponential decay function:

Can determine the amount <em>A</em> of a radioactive substance present at time <em>t. A₀ </em>represents the initial amount and <em>P</em> is the half-life of the substance.
We are given that a substance loses 70% of its radioactivity in 500 days, and we want to determine the period of the half-life.
In other words, we want to determine <em>P. </em>
Since the substance has lost 70% of its radioactivity, it will have only 30% of its original amount. This occured in 500 days. Therefore, <em>A</em> = 0.3<em>A₀</em> when <em>t</em> = 500 (days). Substitute:

Divide both sides by <em>A₀:</em>

We can take the natural log of both sides:

Using logarithmic properties:

So:

Take the reciprocal of both sides:

Use a calculator:

The half-life of the substance is about 288 days.
(600 - 148 ) / (divided) by 5 = Pages read per day after first day