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3 years ago

In a survey, a group of students were asked their favorite sport. Eighteen students chose “other” sports.

Mathematics

1 answer:

Nina [5.8K]3 years ago

6 0

a. How many students participated?

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it takes a baseball team 2 hours to complete a game.how long will it take to complete 2/3 of the game.

natima [27]

2 hours is 120 minutes
120 min * 2/3 is 80 minutes

5 0

3 years ago

Rearrange x=3g+2 to make g the subject.

mina [271]

We have: x = 3g + 2

Subtract 2 from the both sides,
x - 2 = 3g + 2 - 2
x - 2 = 3g

Now, Divide 3 from both sides,
(x-2)/3 = 3g/3
g = x-2 / 3

In short, Your Answer would be x-2 /3

Hope this helps!

6 0

3 years ago

Read 2 more answers

What is the measure of x

Dafna1 [17]

Answer:

58 degrees

Step-by-step explanation:

XYZ is 90 degrees. XYO is 32 degrees. Angle x takes up the space leftover in the right angle, so simply subtract 32 from 90.

90-32= 58

Hope this help! (if it does pls consider giving me brainliest)

7 0

2 years ago

When the sample size and the sample proportion remain the same, a 90 percent confidence interval for a population proportion p w

deff fn [24]

Answer:

A 90% confidence interval for p will be narrower than the 99% confidence interval.

Step-by-step explanation:

The formula to compute the (1 - α) % confidence interval for a population proportion is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Here $\hat p$ is the sample proportion.

The margin of error of the confidence interval is:

$MOE= z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The MOE is dependent on:

Confidence level
Standard deviation
Sample size

The MOE is directly related to the confidence level and standard deviation.

So if any of the two increases then the MOE also increases, thus widening the confidence interval.

And the MOE is inversely related to the sample size.

So if the sample increases the MOE decreases and vice versa.

It is provided that the sample size and the sample proportion are not altered.

The critical value of z for 90% confidence level is:

$z_{\alpha/2}= z_{0.10/2}=z_{0.05}=1.645$

And the critical value of z for 99% confidence level is:

$z_{\alpha/2}= z_{0.05/2}=z_{0.05}=1.96$

So as the confidence level increases the critical value increases.

Thus, a 90% confidence interval for p will be narrower than the 99% confidence interval.

6 0

3 years ago

The speeds on the interstate are normally distributed with a mean of 70 mph and a standard deviation of 5 mph. Approximately wha

attashe74 [19]

$\mathbb P(60$

The empirical rule asserts that approximately 95% of a distribution falls within two standard deviations of the mean.

6 0

4 years ago