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3 years ago

In a survey, a group of students were asked their favorite sport. Eighteen students chose “other” sports.

Mathematics

1 answer:

Nina [5.8K]3 years ago

6 0

<span>a. How many students participated?

</span>

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Please help ASAP THIS IS MY FINAL QUESTION!!!! 20 points!!!!

givi [52]

Answer:

y= 1/2x-3

Step-by-step explanation:

2y - x = 8

First find the slope

2y = x+8

Divide by 2

2y/2 = x/2 +8/2

y = 1/2 x +4

The slope is 1/2 ( y=mx+b where m is the slope and b is the y intercept)

When lines are parallel they have the same slope)

Using y = mx+b

y =1/2x+b

Substituting the point (4,-1) into the equation

-1 =1/2(4)+b

-1 = 2+b

-3 =b

The equation of the line is

y= 1/2x-3

4 0

3 years ago

A cone has a radius of 10 cm and and height of 9 cm. What is the approximate volume of the cone? Use 3.14 for π.

astraxan [27]

Answer:

The volume of the cone is $942cm^3$

Step-by-step explanation:

The given cone has a radius of 10 cm and and height of 9 cm.

The volume of a cone is given by:

$V=\frac{\pi r^2h}{3}$

We substitute r=10 and h=9 , $\pi=3.14$ to obtain:

$V=\frac{3.14*10^2*9}{3}$

Simplify exponents to get:

$V=\frac{3.14*100*9}{3}$

Simplify:

$V=314*3\\V=942cm^3$

Therefore the volume of the cone is $942cm^3$

8 0

3 years ago

Write an equation in slope-intercept form for the line that satisfies the following condition. slope 7, and passes through (5, 3

allsm [11]

Y = mx + b
slope(m) = 7
(5,30)...x = 5 and y = 30
now we sub and find b, the y int
30 = 7(5) + b
30 = 35 + b
30 - 35 = b
-5 = b

so ur equation is : y = 7x - 5 <==

7 0

3 years ago

For the graphed function f(x) = -(5)* - 3 + 2, calculate the average rate of change from x = 3 to x = 4.

Ilia_Sergeevich [38]

Answer:

-4

Step-by-step explanation:

The average rate of change from x=a to x=b of f(x) is $\frac{f(b)-f(a)}{b-a}$

The given function is $f(x)=-5^{x-3}+2$ .

$f(4)=-5^{4-3}+2=-3$ .

$f(4)=-5^{3-3}+2=1$ .

The average rate of change from x=3 to x=4 is given by:

$\frac{f(4)-f(3)}{4-3}$

$\frac{-3-1}{4-3}=-4$

7 0

3 years ago

Find the value of the expressions 3x^3-2y^3-6x^2y^2+xy for x=2/3 and y=1/2

fiasKO [112]

Hi!

$3x^3-2y^3-6x^2y^2+xy=\\\\=3\cdot(\frac{2}{3})^3-2\cdot(\frac{1}{2})^3-6\cdot(\frac{2}{3})^2\cdot(\frac{1}{2})^2+\frac{2}{3}\cdot\frac{1}{2}=\\\\=3\cdot\frac{8}{27}-2\cdot\frac{1}{8}-6\cdot\frac{4}{9}\cdot\frac{1}{4}+\frac{1}{3}=\\\\=\frac{8}{9}-\frac{1}{4}-\frac{2}{3}+\frac{1}{3}=\frac{8}{9}-\frac{1}{4}-\frac{1}{3}=\frac{32}{36}-\frac{9}{36}-\frac{12}{36}=\boxed{\frac{11}{36}}$

5 0

3 years ago