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3 years ago

9. If y = kx, where k is a constant, and y = -3 when x = 6, what is the value of x when y = 12?

Mathematics

2 answers:

____ [38]3 years ago

6 0

Answer:

x would be -24

Step-by-step explanation:

since k is a constant, we have to find out what k is from the equation

. -3=6(k) divide both sides by 6 to get that k is -0.5/-1/2.

then, solve for what x is when y is 12 by setting up the equation 12=(-0.5)x. this would result in x being -24

NemiM [27]3 years ago

4 0

Hey there! :)

Answer:

x = -24.

Step-by-step explanation:

Plug in the values to find the value of 'k':

-3 = k(6)

Divide both sides by 6 to solve for 'k':

-3/6 = k

k = -1/2

Plug this into the equation to solve for the value of x when y= 12:

12 = -1/2(x)

Divide both sides by -1/2:

-24 = x

x = -24.

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Answer:

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4 years ago

Read 2 more answers

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timurjin [86]

Answer:

Step-by-step explanation:

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2 years ago

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Learn more about binomial random variable here

brainly.com/question/14282621

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1 year ago