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katovenus [111]
3 years ago
14

A population of size 3,624 grows at a rate of 3% per year, compounded continuously. How big will the population be in 2 years?

Mathematics
1 answer:
rodikova [14]3 years ago
8 0

Answer:

Step-by-step explanation:

The continuous compound formula is

y=Pe^{rt where P is the principle or starting value, r is the growth rate in decimal form, and t is the time in years. For us:

y=3624e^{(.03)(2)}\\y=3624e^{.06}\\y=3624(1.061836547)\\y=3848.09

which would probably round to just 3848 people.

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Answer:

The probability is P(|p-\^{p}| >  0.03)  =   0.0040

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From the question we are told that

   The population proportion is p =  0.07

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=>   P(|p-\^{p}| >  0.03)  =  1 -  P( 0.07-0.03  \le \^{p} \le 0.03+ 0.07 )

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=> P(|p-\^{p}| >  0.03)  =  1 -  P(-2.88  \le Z \le 2.88 )

=>   P(|p-\^{p}| >  0.03)  =   1 - [P(Z \le 2.88) - P(Z \le -2.88)]

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and

       P(Z \le -2.88)  = 0.0020

So

     P(|p-\^{p}| >  0.03)  =   1 - [0.9980 - 0.0020]

=>   P(|p-\^{p}| >  0.03)  =   0.0040

     

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