Answer:
I hope it helped you and you understood it.
The ideal mechanical advantage of this car Jack: 30cm
What is Ideal mechanical advantage?
The length of the effort arm of a lever divided by the length of the resistance arm represents the optimal mechanical advantage. The IMA is typically calculated as the resistance force (Fr) divided by the effort force (Fe). IMA is also equal to the product of the load's travel distance (dr) and the distance over which the effort is applied (de).
The Handle of the car jack = 75cm
The car lifted by the jack = 2.5cm
According to the formula:
Ideal mechanical advantage = The resistance force / The effort force
or, (Fr/Fe)
IMA = 75 / 2.5
IMA = 30cm
Hence, Ideal mechanical advantage of the car jack = 30cm
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Answer:
(0.500, 1.090)
Step-by-step explanation:
Given that a university dean is interested in determining the proportion of students who receive some sort of financial aid.
A sample of (random) 200 students taken and 118 were found out receiving financial aid.
Sample proportion p = ![\frac{118}{200} \\=0.59](https://tex.z-dn.net/?f=%5Cfrac%7B118%7D%7B200%7D%20%5C%5C%3D0.59)
![q-1-o=0.41\\std error = \sqrt{pq/n} =0.0348](https://tex.z-dn.net/?f=q-1-o%3D0.41%5C%5Cstd%20error%20%3D%20%5Csqrt%7Bpq%2Fn%7D%20%3D0.0348)
For margin of error we use Z critical value as this is proportion and also sample size is large. np and nq both are greater than 5.
So margin of error = 2.58*std error = 0.090
Confidence interval
=![(0.500,1.090)](https://tex.z-dn.net/?f=%280.500%2C1.090%29)
Answer:
No, does not differ.
Step-by-step explanation:
Given that there are two intersections route 7 and route 62.
At the intersection of Route 7 and North Shrewsbury in Clarendon, Vermont, 154 vehicles were observed to encounter a yellow light in the indecision zone, and 21 of them ran the red light. At the intersection of Route 62 and Paine Turnpike in Berlin, Vermont, 183 vehicles entered the intersection in the indecision zone, and 20 ran the red light.
Let p1 be the first proportion and p2 the second
We want to test whether these two proportions differ
![H_0: p_1 = p_2\\H_a: p_1 \neq p_2](https://tex.z-dn.net/?f=H_0%3A%20p_1%20%3D%20p_2%5C%5CH_a%3A%20p_1%20%5Cneq%20p_2)
(two tailed test at 5% significance level)
test statistic = ![\frac{p_1-p_2}{\bar p (1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})}](https://tex.z-dn.net/?f=%5Cfrac%7Bp_1-p_2%7D%7B%5Cbar%20p%20%281-%5Cbar%20p%29%28%5Cfrac%7B1%7D%7Bn_1%7D%2B%5Cfrac%7B1%7D%7Bn_2%7D%29%7D)
![p_1 = 0.1363\\p_2 = 0.1093](https://tex.z-dn.net/?f=p_1%20%3D%200.1363%5C%5Cp_2%20%3D%200.1093)
Z statistic = ![0.7554](https://tex.z-dn.net/?f=0.7554)
p value = 0.4473
Since p >0.05 accept null hypothesis.
There is no significant difference and the proportion of redlight runners does not differ between the two intersections
Answer:
16 4/5 inches
Step-by-step explanation:
We can find the amount it will grow by taking the rate it grows times the time
growth = rate* time
= 2 2/5 * 7
Changing the mixed number to an improper fraction
2 2/5 = (5*2+2)/5 = 12/5
growth = (12/5)*7
=84/5 inches
Changing this back to a mixed number
5 goes into 84 16 times (5*16 = 80 ) with 4 left over
16 4/5 inches