Answer:
(30, ∞)
Step-by-step explanation:
b – 27 > 3
Add 27 to both sides
b > 30
In interval notation
(30, ∞)
Answer: The commutative property
Step-by-step explanation: The commutative property is where an equations can be swapped and not change the answer. The following is true with that problem.
Let us assume the small integer to be = x
Then
The second consecutive greater integer = x + 1
The sum of two consecutive integers is already given in the question and it is 125. based on this given information, the answer to the question can be easily reached.
So
x + x+ 1 = 125
2x + 1 = 125
2x = 125 - 1
2x = 124
x = 124/2
= 62
Then
The largest of the two integers = x + 1
= 62 + 1
= 63
So 63 is the largest integer among the two consecutive integers. I hope the procedure is not very tough for you to understand.
X + x + 1 + x + 2 < 400
3x + 3 < 400
3x < 397
x < 132.33333...
the smallest number has to be smaller than 132. 33
There aren't any answer options so I will just simplify the expression:
10(2p+q)
20p+10q
