Having trouble with this geometry question! Someone help! Please.

Mathematics

1 answer:

iris [78.8K]3 years ago

4 0

44°, because the measure of the left side of angle B=112°, 180°-112°=68°, so the measure of the right side of angle B=68°, and since side BE and side CE are congruent and have the same length measurements, then angle C and the right side of angle B are also congruent. All angles of a triangle must add up to 180°, and since you have angle C as 68° and angle B as 68°, 68°+68°= 136°, and 180°-136°=44°

You might be interested in

Your business partner describes this as a high positive correlation. Is your partner correct? Why or why not? (2 points)

zaharov [31]

Answer:

if the points are in a straight line going upward then they are corect

but if the points are scattered they are wrong its hard to answer this question he graph to look at

4 0

3 years ago

Write the following as comparison as a ratio reduced to lowest terms of 149 minutes to 9 hours

drek231 [11]

779836936983163398138

6 0

3 years ago

How many ways are there to choose a soccer team consisting of 3 forwards, 4 midfield players, and 3 defensive players, if the pl

klio [65]

Using the combination formula, it is found that there are 47,040 ways to form a soccer team.

<h3>What is the combination formula?</h3>

Each of the different groups or selections can be formed by taking some or all of a number of objects, irrespective of their arrangments is called a combination.

$^mC_k = \dfrac{m!}{k! \times (m-k)!}$

A soccer team consisting of 3 forwards, 4 midfield players, and 3 defensive players, if the players are chosen from 8 forwards, 6 midfield players and 8 defensive players

Since they are independent of each other, the total number of combinations will be;

$^mC_k = \dfrac{8!}{3! \times (5)!} \times \dfrac{6!}{4! \times (2)!} \times \dfrac{8!}{3! \times (5)!} \\\\^mC_k =47,040$