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kiruha [24]
3 years ago
13

The expression 5x2 + 2x + 3 represents the area of a square. The area of

Mathematics
2 answers:
ioda3 years ago
8 0

Answer:

Step-by-step explanation:

lora16 [44]3 years ago
6 0
The correct answer is C
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Solve the inequality.    <br>       3m ≤ –9<br> A.m ≥ –3<br> B.m ≤ –3 <br> C.m ≥ 6  <br> D.m ≤ –6
marin [14]
3m \leq -9\ /:3 \ \ \ \Rightarrow\ \ \ m \leq -3\ \ \ \Rightarrow\ \ \ Ans.\ B
6 0
3 years ago
I live in United States and I want to move to Scotland I'm trying to understand the conversion of money I understand one US doll
NeTakaya
4400 because you multiply 5000 with 0.88 to get your answer.
4 0
3 years ago
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56 out of the 56 employees at the sports shop are part-time employees. What percentage of the employees at the sports shop work
ankoles [38]

Answer:

100%

Step-by-step explanation:

Since 56/56 employees at the sports shop work part time, that means 100% of them do, or all of them.

7 0
2 years ago
Two lines intersect. Find the value of b and c.<br> bº<br> 42°
yaroslaw [1]

Answer:

b=42 degrees

c= 138 degrees

Step-by-step explanation:

B and the 42 degrees shown are congruent angles so therefore both are 42 degrees

To find C: We know that combining the 42 degrees and Angle C would form a flat angle or 180 degree angle, so therefore

subtract 180 with 42 to get Angle C

180-42= 138

4 0
3 years ago
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The differential equation y′′=0 has one of the following two parameter families as its general solution: yyyy=C1ex+C2e−x=C1cos(x
svet-max [94.6K]

Answer:

y_c = 2 + 10*x

Step-by-step explanation:

Given:

                                                y'' = 0

Find:

- The solution to ODE such that y(0) = 2, y'(0) = 10

Solution:

- Assuming a solution y = Ce^(mt)

So,                                y' = C*me^(mt)

                                    y'' = C*m^2e^(mt)

- Back substitute into given ODE, we get:

                                    y'' = C*m^2e^(mt) = 0

                                    e^(mt) can not be equal to zero

- Hence,                       m^2 = 0

                                     m = 0 , 0 - (repeated roots)

- The complimentary function for repeated roots is:

                                    y_c = (C1 + C2*x)*e^(m*t)

                                    y_c = C1 + C2*x  

- Evaluate @ y(0) = 2

                                    2 = C1 + C2*0

                                    C1 = 2

-Evaluate @ y'(0) = 10

                                    y'(t) = C2 = 10

Hence,                         y_c = 2 + 10*x

5 0
3 years ago
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