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3 years ago

Given that P = (2, 9) and Q = (4, 14), find the component form and magnitude of vector PQ.

1 answer:

6 0

We are asked to determine the lengths of the line segment drawn with these points as endpoints. The equation of the distance between points is,
d = sqrt ((y2 - y1)² + (x2 - x1)²)
Substituting the coordinates of the points,
d = sqrt ((14 - 9)² + (4 - 2)²)
The numerical value for d is approximately 5.39.

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A black line is shorter than a white line.the white line is shorter than a gray line. Is the black line longer or shorter than t

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Black is shorter than grey

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3 years ago

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In 4.59 what does the nine stand for?

Kisachek [45]

The 9 stands for hundredths

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3 years ago

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Which points are on the perpendicular bisector of the given segment? Check all that apply. Please explain how you got your answe

ser-zykov [4K]

First, you have to find the equation of the perpendicular bisector of this given line.
to do that, you need the slope of the perpendicular line and one point.
Step 1: find the slope of the given line segment. We have the two end points (10, 15) and (-20, 5), so the slope is m=(15-5)/(10-(-20))=1/3
the slope of the perpendicular line is the negative reciprocal of the slope of the given line, m=-3/1=-3
step 2: find the middle point: x=(-20+10)/2=-5, y=(15+5)/2=10 (-5, 10)
so the equation of the perpendicular line in point-slope form is (y-10)=-3(x+5)

now plug in all the given coordinates to the equation to see which pair fits:
(-8, 19): 19-10=9, -3(-8+5)=9, so yes, (-8, 19) is on the perpendicular line.

try the other pairs, you will find that (1,-8) and (-5, 10) fit the equation too. (-5,10) happens to be the midpoint.

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3 years ago

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Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)

Mashcka [7]

The cone equation gives

$z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2$

which means that the intersection of the cone and sphere occurs at

$x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92$

i.e. along the vertical cylinder of radius $\dfrac3{\sqrt2}$ when $z=\dfrac3{\sqrt2}$ .

We can parameterize the spherical cap in spherical coordinates by

$\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle$

where $0\le\theta\le2\pi$ and $0\le\varphi\le\dfrac\pi4$ , which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is $\dfrac3{\sqrt2}$ . So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

$\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4$

Now the surface area of the cap is given by the surface integral,

$\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du$
$=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}$
$=18\pi\left(1-\dfrac1{\sqrt2}\right)$
$=9(2-\sqrt2)\pi$

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3 years ago

5.7y-5.2=y/2.5 how to solve

11Alexandr11 [23.1K]

5.7y-5.2=y/2.5

Add 5.2 to both sides:

5.7y = y/2.5 + 5.2

y/2.5 = 0.4y

5.7y = 0.4y + 5.2

Subtract 0.4y from both sides:

5.3y = 5.2

Divide both sides by 5.3:

y = 5.2/5.3

y = 0.98113

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2 years ago

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