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Readme [11.4K]
3 years ago
5

Given that P = (2, 9) and Q = (4, 14), find the component form and magnitude of vector PQ.

Mathematics
1 answer:
polet [3.4K]3 years ago
6 0
We are asked to determine the lengths of the line segment drawn with these points as endpoints. The equation of the distance between points is,
                              d = sqrt ((y2 - y1)² + (x2 - x1)²)
Substituting the coordinates of the points,
                               d = sqrt ((14 - 9)² + (4 - 2)²)
The numerical value for d is approximately 5.39. 
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Black is shorter than grey

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In 4.59 what does the nine stand for?
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The 9 stands for hundredths

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Which points are on the perpendicular bisector of the given segment? Check all that apply. Please explain how you got your answe
ser-zykov [4K]
First, you have to find the equation of the perpendicular bisector of this given line. 
to do that, you need the slope of the perpendicular line and one point.
Step 1: find the slope of the given line segment. We have the two end points (10, 15) and (-20, 5), so the slope is m=(15-5)/(10-(-20))=1/3
the slope of the perpendicular line is the negative reciprocal of the slope of the given line, m=-3/1=-3 
step 2: find the middle point: x=(-20+10)/2=-5, y=(15+5)/2=10      (-5, 10)
so the equation of the perpendicular line in point-slope form is (y-10)=-3(x+5)

now plug in all the given coordinates to the equation to see which pair fits:
(-8, 19): 19-10=9, -3(-8+5)=9, so yes, (-8, 19) is on the perpendicular line. 

try the other pairs, you will find that (1,-8) and (-5, 10) fit the equation too. (-5,10) happens to be the midpoint. 

4 0
3 years ago
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Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
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=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
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3 years ago
5.7y-5.2=y/2.5 how to solve
11Alexandr11 [23.1K]

5.7y-5.2=y/2.5

Add 5.2 to both sides:

5.7y = y/2.5 + 5.2

y/2.5 = 0.4y

5.7y = 0.4y + 5.2

Subtract 0.4y from both sides:

5.3y = 5.2

Divide both sides by 5.3:

y = 5.2/5.3

y = 0.98113

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2 years ago
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