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igomit [66]
3 years ago
5

How many integers are between sqrt 37 and 5*sqrt 11?

Mathematics
1 answer:
34kurt3 years ago
8 0

Answer:

There are 10 integers between the given values

Step-by-step explanation:

We start by finding approximations of the two real values given that include square roots of non-perfect-square numbers:

\sqrt{37} \approx6.0827

then this point is located in between the integers 6 and 7 on the x-axis.

5\,\sqrt{11} \approx 16.58

therefore, it is located between the integers 16 and 17 on the number line.

Then between \sqrt{37}, and 5\,\sqrt{11}, we have the following integers:

7, 8, 9, 10, 11, 12, 13, 14, 15, 16.

That is 10 integers

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12,24 etc

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4 and 6 both go into 12 evenly

4*3 = 12

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12 is the least common denominator

We could also use 24

4*6 = 24

It is a common denominator, but not the least common denominator

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A rectangular pyramid has a height of 10 meters. The base measures 8 meters in length and 12 meters in width. Two different tria
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2 years ago
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3 years ago
A certain region currently has wind farms capable of generating a total of 2500 megawatts ​(2.5 ​gigawatts) of power. Complete p
marishachu [46]

Answer:

<u>The correct answer is A. 7,665'000,000 kilowatt-hours per year and B. 766,500 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,500 Megawatts or 2.5 Gigawatts

2. Let's resolve the questions a and b:

Part A

Assuming wind farms typically generate 35​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,500 * 0.35 = 875 Megawatts

875 Megawatts = 875 * 1,000 Kilowatts = 875,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

875.000 Kw generated by the farms means that are capable of produce 875,000 kw per hour of energy

875,000 * 24 = 21'000,000 kilowatt-hours per day

<u>21'000,000 * 365 = 7,665'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (7,665'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  7,665'000,000/10,000 = 766,500</u>

4 0
3 years ago
1 point
ludmilkaskok [199]

Answer:

last option

Step-by-step explanation:

y + 3 = 2 ( x - 1 )

⇒ y + 3 = 2x - 2

⇒ y = 2x - 5

4 0
3 years ago
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