3 years ago

2 to the square root of 6 + 3 to the square root of 54

Mathematics

1 answer:

sdas [7]3 years ago

3 0

Answer:

I think it's 12×54 but im probs wrong

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HELP 1/7z+2=-6/7z what’s the solution set please send help I’m suffocating under homework

Snezhnost [94]

Isolate the z. Note the equal sign. Subtract 1/7z to both sides

1/7z (-1/7z) + 2 = -6/7z (-1/7z)

2 = -6/7z - 1/7z

Simplify. Combine like terms

2 = -7/7z

2 = -1z

Isolate the z. Divide -1 from both sides

(2)/-1 = (-1z)/-1

z = 2/-1

z = -2

-2 is your answer

hope this helps

8 0

3 years ago

The sum of two numbers is −21. One number is 55 less than the other. Find the numbers.

nika2105 [10]

Answer:

x = 17 y= -38

Step-by-step explanation:

x + y = -21

y = x - 55

It doesn't matter whether x or y is 55 less than the other right now.

substitute for y:

x + x - 55 = -21

solve for x:

2x = 34

x = 17

solve for y:

17 + y = -21

y = -38

6 0

4 years ago

Anthony, Josh, and Dominic worked a combined 7 hours today. Dominic worked twice as many hours as Anthony did with an extra hour

Nataliya [291]

Dominic worked 5 hours
anthony worked 2 hours
josh worked 0 hours

4 0

4 years ago

Find the area of a polygon with vertices at (1, 3), (7, 3), (7, 7), and (4, 7). a. 24 units2 b. 10 units2 c. 12 units2 d. 18 uni

maria [59]

Answer:

Option D

Step-by-step explanation:

Vertices of the polygon are A(1, 3), B(7, 3), C(7, 7), D(4, 7)

Measure of AB = 7 - 1 = 6 units

Measure of BC = 7 - 3 = 4 units

Measure of CD = 7 - 4 = 3 units

From the figure attached,

Area of the trapezoid = $\frac{1}{2}(AB+CD)(BC)$ [Here, AB and CD are the parallel bases and BC is the height of the trapezoid]

= $\frac{1}{2}(6+3)(4)$

= 18 square units

Therefore, Option D will be the correct option.

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3 years ago

grabriella volunteers at the hospital every 4th day.she volunteers at the food pantry every 6th day.she volunteered at the hospi

IgorLugansk [536]

Answer:

April 12th

Step-by-step explanation:

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3 years ago