Answer:
1.
Vert. asymptote: x = {-3, 2}
Horiz. asymptote: y = 0
x-int: None
Question 3.
a. There is no hole
b. Vert. asymptote: x = {-2, 2}
c. f(x) = 0: x = {0, -1/2}
d. The graph has no hole at (-2, 4)
Question 4.
a. Vert. asymptote: x = {-2, 2}
b. f(x) = 0: x = {0, -1/2}
c. Horizontal asymptote: y = 2
d. The graph has no hole
I'm a bit confused. Some of the things stated in the question aren't true like how there are holes in places where there aren't.
Here's an example
Y=5x + 10
if x is equal to 5 you would make it
Y=5(5)+10.
basically, just replace the x with what it's equal to.
Answer:
g(x) = (-1/25)x + (203/25)
Step-by-step explanation:
The general equation for a line is slope-intercept form is:
y = mx + b
In this form, "m" represents the slope and "b" represents the y-intercept.
We know that perpendicular lines have opposite-signed, reciprocal slopes of the original line. Therefore, if the slope of f(x) is m = 25, the slope of g(x) must be m = (-1/25).
To find the y-intercept, we can use the newfound slope and the values from the given point to isolate "b".
g(x) = mx + b <----- General equation
g(x) = (-1/25)x + b <----- Plug (-1/25) in "m"
8 = (-1/25)(3) + b <----- Plug in "x" and "y" from point
8 = (-3/25) + b <----- Multiply (1/25) and 3
200/25 = (-3/25) + b <----- Covert 8 to a fraction
203/25 = b <----- Add (3/25) to both sides
Now that we know both the values of the slope and y-intercept, we can construct the equation of g(x).
g(x) = (-1/25)x + (203/25)
In points form the answer is (-8,-4) and in equation form the answer is x=-8, y=-4
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Step-by-step explanation:
120ft³ = 3ft × 4ft × 10ft
120ft³ = 1ft × 1ft × 120ft
120ft³ = 2ft × 2ft × 30ft
120ft³ = 5ft × 3ft × 8ft
...
Taking fractions or mixed numbers as dimensions, you can give infinitely many such shapes with a volume of 120ft³.
