what is required of a proportional relationship that is not required of a general linear relationship

2 answers:

8 0

Pertains to y-intercept is then 0.

It introduces the relationship between two variables and is called correlation. Proportionality or variation is state of relationship or correlation between two variables It has two types: direct variation or proportion which states both variables are positively correlation. It is when both the variables increase or decrease together. On the contrary, indirect variation or proportion indicates negative relationship or correlation. Elaborately, the opposite of what happens to direct variation. One increases with the other variables, you got it, decreases. This correlations are important to consider because you can determine and identify how two variables relates with one another. Notice x = y (direct), y=1/x (indirect)

Maksim231197 [3]3 years ago

8 0

Answer:

It has to go through the origin.

Step-by-step explanation:

The solid line must pass through the origin point (0,0) to be considered proportional.

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You have ducks and sheep in a farmyard. If there are 102 legs and 33 heads how many of each do you have? Set up and solve it to

RUDIKE [14]

There will be 18 sheep and 15 ducks.
18+15=33
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15 ducks x 2 legs per duck = 30 legs

72+30= 102 legs in all

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yuradex [85]

Answer:

Step-by-step explanation:

Hello!

Given the variables

X₁: Weight of a safety helmet for racers

X₂: Price of a safety helmet for racers

Note, there is n= 17 observed values for each variable so for all calculations I'll use this number and disregard the 18 mentioned in the text.

a) Scatterplot in attachment.

b) If you look at the diagram it seems that there is a negative linear regression between the price and the weight of the helmets, meaning, the higher the helmet weights, the less it costs.

c) The estimated regression equation is ^Yi= a + bXi

n= 17; ∑Y= 6466; ∑Y²= 3063392; ∑X= 1008; ∑X²= 60294; ∑XY= 367536

Y[bar]= 380.35; X[bar]= 59.29

$b= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} } = \frac{367536-\frac{1008*6466}{17} }{60294-\frac{(1008)^2}{17} } = -30.18$