x + y = 24 where x and y are the 2 parts of diagonal Other diagonal wil be smaller that 24.
x^2 + z^2 = 13^2
y^2 + z^2 = 20^2 where z = 0.5 * length of smaller diagonal)
form last 2 equations
y^2 - x^2 = 20^2 - 13^2 = 231
now y = 24-x so we have
(24 - x)^2 - x^2 = 231
576 - 48x = 231
48x = 345
x = 7.1875
z^2 = 13^2 - 7.1875^2 = 117.34
z = 1.83
so smaller diagonal = 21.66 cm
looks like its the third choice.
Answer: The required equation is 
Step-by-step explanation: We are given to write the following statement as an equation :
"The sum of one-third of a number, one-half of a number and twice the number is thirty-four".
Let the number be represented by x.
Then, one-third of the number is
one-half of the number is
and twice the number is 
Therefore, as an equation, the given statement is written as:

Thus, the required equation is 
Answer:
just multiply two numbers on the rombus and you have your answer