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-Dominant- [34]
3 years ago
6

Solve for n: -6(n -8) = 4(12 -5n) + 14n.​

Mathematics
2 answers:
Setler [38]3 years ago
6 0

Answer:

This is a very classical type of equation in which, the solution is basically any number and it is known as an "Identity". So it has infinite solutions

Step-by-step explanation:

  • Apply the distributive law to both sides of the equation:

-6(n-8) = 4(12-5n)+14n

-6n-6*(-8) = 4*12+4*(-5n) + 14n

  • Reduce similar terms

-6n+48=48-20n+14n

-6n+48=48-6n

  • From here it is clear them to see that by adding -48 and 6n to both sides one obtains the identity 0 = 0

-6n+48=48-6n

-6n +6n + 48 -48 = 48 -48 - 6n + 6n

0 = 0

  • So every time you find this kind of problem and after reducen the equation you end up with a true statement, then the equation has infinite solutions

Alexxx [7]3 years ago
5 0

Answer:

infinite solutions

Step-by-step explanation:

Given

- 6(n - 8) = 4(12 - 5n) + 14n ← distribute parenthesis on both sides

- 6n + 48 = 48 - 20n + 14n, that is

- 6n + 48 = 48 - 6n ( add 6n to both sides )

48 = 48 ← True

This indicates that the equation is true for any value of n

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A half-life of the isotope is 15 days and at start its mass is 32 g.
A table:
              t:                 m:
              0                32 g
             15               16 g
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In the first column is used an arithmetic sequence ( a 1 = 0, d = 15 ).
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3 years ago
Can some one answer quickly please
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Answer:

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Step-by-step explanation:

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3 years ago
The sum of 12.6, 31, and 5.4 is greater then 20
Dmitry [639]

Answer:

49>20

Step-by-step explanation:

12.6 + 31 + 5.4 = 49 >20

5 0
2 years ago
perform the indicated operation write the answer with the correct number of significant digits 895.136 m + 276.51 m
Serggg [28]

Answer:

1171.65 m

Step-by-step explanation:

895.136m  \:  +  \: 276.51m \\  = 1171.646 \: m \\ following \: manipulation \: rules \\ in \: addition \: we \: take \: the \: least \: number \: of \: decimal \: places \\  = 1171.65 \: m \: (6 \: significant \: figures)

6 0
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A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec
zhenek [66]

Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

.41 = .73 x .66

.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

4 0
3 years ago
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