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lutik1710 [3]
3 years ago
8

What is the solution to the inequality below? 

Mathematics
1 answer:
irina1246 [14]3 years ago
8 0
_Award brainliest if helped! 
 B.  -7≤X≤7
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1. Make up two equations, one that is true and one that is false. Do not state which equation is true and which is false. Your c
N76 [4]
1. The equations that I can think of are,
                                    3 + 1 = 11 - 6
and 
                                    8 - 1 = 6 + 1

2. An example of equation that uses the variable x,
                                     6x - 2x = 8
It may be required of you to perform certain steps in order to determine the value of x. 
6 0
3 years ago
Read 2 more answers
What is...............2(4x-3)-8=4+2x
Lyrx [107]

Answer:

\huge\boxed{x=3}

Step-by-step explanation:

\text{Solve the equation for 'x'.}\\\\\\2(4x-3)-8=4+2x\\\\8x-6-8=4+2x\\\\8x-14=4+2x\\\\8x-14+14=4+14+2x\\\\8x=18+2x\\\\8x-2x=18+2x-2x\\\\6x=18\\\\\frac{6x=18}{6}\\\\\boxed{x=3}\\\\\\\boxed{\text{The correct answer should be: } X= 3}\\\\\\\text{Hope this helps you!}

7 0
3 years ago
Help plz idk okhehehehehe​
TiliK225 [7]
That is the answer for the first one

6 0
2 years ago
Value of the pronumeral and describe the rule.<br>4,1,-2,p,-8,-11​
Citrus2011 [14]

Answer:

p = -5

every element in the sequence is created by subtracting 3 from the pervious element.

Step-by-step explanation:

I am not sure you put every necessary information here.

but I'd the visible information is truly everything, then it's is trivial.

the difference between 4 and 1 is ... well, -3. meaning we subtract 3 from 4 to get 1.

we suspect this is the rule and keep trying.

1 -3 = -2

hey it works.

and -8 -3 = -11

hey, also correct.

and the difference between -2 and -8 is -6, and when we place another item in between (p), we cut that in half again to -3. so, it is all consistent.

therefore,

p = -2 -3 = -5

the rule is

an = an-1 - 3

6 0
2 years ago
HELP ASAP 5 POINTS...................
11111nata11111 [884]
The answer is A. one of the zeros is x = -1
3 0
2 years ago
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