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3 years ago

What is 28 - ( -15)

Mathematics

2 answers:

bearhunter [10]3 years ago

5 0

Answer:

Step-by-step explanation:

When subtracting a negative number, the negatives cancel out. This gives us 28 + 15 which is 43.

Sidana [21]3 years ago

3 0

Answer:

Step-by-step explanation:

so when subtracting a negative number the number becomes positive and the problem become 28 + 15 because the negative (subtraction) signs cancel out

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If r and s are positive integers, is \small \frac{r}{s} an integer? (1) Every factor of s is also a factor of r. (2) Every prime

Yuri [45]

Answer:

If statement(1) holds true, it is correct that $\small \frac{r}{s}$ is an integer.

If statement(2) holds true, it is not necessarily correct that $\small \frac{r}{s}$ is an integer.

Step-by-step explanation:

Given two positive integers $r$ and $s$ .

To check whether $\small \frac{r}{s}$ is an integer:

Condition (1):

Every factor of $s$ is also a factor of $r$ .

$r \geq s$

Let us consider an example:

$s = 5^2 \cdot 2\\r = 5^3 \cdot 2^2$

$\dfrac{r}{s} = \dfrac{5^3\cdot2^2}{5^2\cdot2} = 10$

which is an integer.

Actually, in this situation $s$ is a factor of $r$ .

Condition 2:

Every prime factor of s is also a prime factor of r.

(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)

Let

$r = 2^2\cdot 5\\s =2^4\cdot 5$

$\dfrac{r}{s} = \dfrac{2^3\cdot5}{2^4\cdot5} = \dfrac{1}{2}$

which is not an integer.

So, the answer is:

If statement(1) holds true, it is correct that $\small \frac{r}{s}$ is an integer.

If statement(2) holds true, it is not necessarily correct that $\small \frac{r}{s}$ is an integer.

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3 years ago

An 8 pack of glue for $3.99 or 1 glue stick for $ .54

gtnhenbr [62]

Answer:

An 8 pack of glue $3.99

Step-by-step explanation

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3 years ago

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line segment AB has endpoints A (7.5,4.2) and B (2.3,5.4). Find the coordinates of the point that divides the line segment direc

Marrrta [24]

9514 1404 393

Answer:

(6.2, 4.5)

Step-by-step explanation:

We want, for some point P, ...

(P -A) / (B -P) = 1 / 3

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4P = B +3A . . . . . . . . add P+3A

P = (B +3A)/4 . . . . . . .divide by 4

Filling in the coordinate values, we can find P to be ...

P = ((2.3, 5.4) +3(7.5, 4.2))/4 = (2.3+22.5, 5.4+12.6)/4

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2 years ago

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musickatia [10]

Answer:

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Step-by-step explanation:

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Soloha48 [4]

Answer:

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Step-by-step explanation:

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