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3 years ago

F(x) = -7x + 1, find f(0)

Mathematics

2 answers:

Vlad [161]3 years ago

5 0

Hey there!!

How do we solve this?

We substitute the value of 0 instead of x

f ( 0 ) = - 7 ( 0 ) + 1

f(0) = 1

Hence, the required answer is 1

Hope my answer helps!!

I am Lyosha [343]3 years ago

3 0

F(x) is also y
So they said find x when y = 0

0= -7x + 1
Minus 1 from both sides

-1 = -7x

Divide-7 from both sides
X = 1/7

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Flura [38]

Answer:

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Step-by-step explanation:

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4 years ago

PQ and QR are 2 sides of a regular 12-sided polygon. PR is a diagonal of the polygon. Work out the size of angle PRQ. You must s

dmitriy555 [2]

Answer:

15°

Step-by-step explanation:

A regular polygon is a polygon in which all the sides and angles of the polygon are equal to each other.

A regular 12-sided polygon is a polygon with 12 equal sides and angles.

The sum of interior angles of a polygon is given as:

sum = (2n - 4)90; where n is the number of sides of the polygon

For a 12 sided polygon:

Sum of interior angles = (2 * 12 - 4)90 = (24 - 4)90 = 20 * 90 = 1800°

Therefore since all the angles are equal, each angle = 1800° / 12 = 150°

Therefore in the question, ∠PQR = 150° (angle of a 12 sided polygon), ∠PRQ = ∠QPR = x

Therefore in triangle PQR:

∠PQR + ∠PRQ + ∠QPR = 180°

150 + x + x = 180

150 + 2x = 180

2x = 30

x = 15°

∠PRQ = 15°

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3 years ago

An army contingent of 104 members is to march behind an army band of 96 members in a parade.

Trava [24]

You can dispose a number $x$ of elements in a matrix-like formation with $n\times m$ shape if and only if $n$ and $m$ both divide $x$ , and also $nm=x$ .

So, we need to find the greatest common divisor between $104$ and $96$ , so that we can use that divisor as the number of columns, and then.

To do so, we need to find the prime factorization of the two numbers:

$104 = 2^3\times 13$

$96 = 2^5 \times 3$

So, the two numbers share only one prime in their factorization, namely $2$ , but we can't take "too many" of them: $104$ has "three two's" inside, while $96$ has "five two's" inside. So, we can take at most "three two's" to make sure that it is a common divisor. As for the other primes, we can't include $3$ nor $13$ , because it's not a shared prime.