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tensa zangetsu [6.8K]
3 years ago
14

Plz help asap.. I have no clue how to do this.

Mathematics
2 answers:
Tema [17]3 years ago
6 0

The 73rd term would be 662.

1 term is +9

10 terms is +90

90x7=630

9x2=18

630+18=648

648+14=662

ANTONII [103]3 years ago
4 0

Answer:

Tn=a + (n-1)d

a= first term = 14

n= This is the term you're looking for... In this case... That's the 73rd term

d=Common difference (since its an AP)

d= second term - first term -- Or 3rd term - 2nd term = 23-14

d=9

T = 14 + (73-1)9

T= 14 + (72)9

T= 14 + 648

T=662.

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Step-by-step explanation:

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Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).
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Answer:

An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

y-1=\frac{1}{4}\left(x+4\right)

Step-by-step explanation:

Given the points

  • (-4,1)
  • (4,3)

Finding the slope between the points (-4,1) and (4,3)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)

m=\frac{3-1}{4-\left(-4\right)}

Refine

m=\frac{1}{4}

Point slope form:

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

in our case,

  • m = 1/4
  • (x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

y-y_1=m\left(x-x_1\right)

y-1=\frac{1}{4}\left(x-\left(-4\right)\right)

y-1=\frac{1}{4}\left(x+4\right)

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

y-1=\frac{1}{4}\left(x+4\right)

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Step-by-step explanation:

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There are 91 dimes in the jar.

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n=200-d

5(200-d) + 10d=1455

1000-5d+10d=1455

1000+5d=1455

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2 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

In this question, we are asked to use calculator to estimate the approximate measure of angle D given its tan value.

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Now to calculate the acute angle D, we will divide through by tan

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