All categories

3 years ago

Plz help asap.. I have no clue how to do this.

Mathematics

2 answers:

Tema [17]3 years ago

6 0

The 73rd term would be 662.

1 term is +9

10 terms is +90

90x7=630

9x2=18

630+18=648

648+14=662

ANTONII [103]3 years ago

4 0

Answer:

Tn=a + (n-1)d

a= first term = 14

n= This is the term you're looking for... In this case... That's the 73rd term

d=Common difference (since its an AP)

d= second term - first term -- Or 3rd term - 2nd term = 23-14

d=9

T = 14 + (73-1)9

T= 14 + (72)9

T= 14 + 648

T=662.

You might be interested in

I need help ASAP because I need done before 4:00pm

Naddik [55]

Answer:

the 13th one is 115

Step-by-step explanation:

8 0

3 years ago

Find the solutions of (x – 4)(x – 4) = 0.

lisabon 2012 [21]

Answer:

Step-by-step explanation:

(x – 4)(x – 4) = 0.

So factor are x-4=0

X=4 (D) is the answer

7 0

3 years ago

I need help ASAP PLEASE please...

lys-0071 [83]

Answer:λ= v X f

v= λ X f

f= λ X v

v= λ / f

Step-by-step explanation:

3 0

3 years ago

mr albernathy perchases a selection of wrenches for his shop. his bill was $78. he buys the same number of $1.50 wrenches and $2

ICE Princess25 [194]

Answer:

Mr. Abernathy purchased 10 of $1.50 wrenches, 10 of $2.50 wrenches, 5 of $4 wrenches and 6 of $3 wrenches.

Step-by-step explanation:

6 0

2 years ago

A media company wants to track the results of his new marketing plan so the video production manager recorded the number of use

konstantin123 [22]

Answer:

$f(x)=5120(5)^{x}$

Step-by-step explanation:

From the image, f(x) and x are rlated by

$f(x)=a( {b})^{x}$

where b is the common ratio

We first find the value for b

$\frac{6400}{5120}= 5$

$\frac{8000}{6400}= 5$

$\frac{10000}{8000} = 5$

$\frac{12500}{10000} = 5$

$\frac{15625}{12500}=5$

so we can say the common ratio, b=5

we put in any value of f(x) and the corresponding value for x to find a value

Let put x=0 and f(x)=5120

This implies that

$5120 = a(5)^{0}$

but

$5^{0} = 1$

Hence a=5120

Thus the equation which model the relationship between the weeks and the viewers is

$f(x)=5120(5)^{x}$

6 0

3 years ago