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Firlakuza [10]
2 years ago
6

What is the measure or ENV

Mathematics
2 answers:
Vlad [161]2 years ago
8 0
First we need to get x
<RNA = <ENV [v.o.a]
8x+12=5x+57
8x-5x=57-12
3x=45
x=15

<ENV= (5×15+57)
<ENV =132
the answer is D
kirza4 [7]2 years ago
5 0

Answer: The answer is (D) 132^\circ.

Step-by-step explanation: We are given a figure where the line segments AE and RV are intersecting at the point N. We are to find the measure of \angle ENV.

Also, given that

\angle ANR=(8x+12)^\circ,\\\\\angle ENV=(5x+57)^\circ.

Since the line segments AE and RV intersect at N, so we have

\angle ANR=\angleENV~[\textup{vertically opposite angles}]\\\\5x+57=8x+12\\\\\Rightarrow8x-5x=57-12\\\\\Rightarrow3x=45\\\\\Rightarrow x=15.

Therefore,

\angle ENV=(5\times 15+57)^\circ=(75+57)^\circ=132^\circ.

Thus, (D) is the correct option.

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An artist cuts the bottom 4 inches from an empty sphere with a radius of 12 inches to make a bowl. How long, to the nearest tent
Zolol [24]

We have been given that an artist cuts the bottom 4 inches from an empty sphere with a radius of 12 inches to make a bowl. We are asked to find the length of the rim of the bowl.

The rim of the bowl will be equal to the perimeter of circle with radius of 12 inches.

\text{Perimeter of circle}=2\pi r, where r represents radius of circle.

\text{Perimeter of circle}=2\pi (12\text{ inches})

\text{Perimeter of circle}=24\pi \text{ inches}

\text{Perimeter of circle}=75.39822 \text{ inches}

\text{Perimeter of circle}\approx 75.4 \text{ inches}

Therefore, the rim of the bowl is approximately 75.4 inches.

6 0
3 years ago
The table shows data from a survey about the amount of time students spend doing homework each week. The students were either in
satela [25.4K]

Answer:

The correct option is: The college spread is best described by the standard deviation. The high school spread is best described by the IQR.

Step-by-step explanation:

We have given a table. According to that table  a survey about the amount of time students spend doing homework each week has been conducted. The students were either in college or in high school. Now which of the choices below best describes how to measure the spread of this data.

The correct option is: The college spread is best described by the standard deviation. The high school spread is best described by the IQR.

5 0
3 years ago
Read 2 more answers
Cosx+1/sin^3x=cscx/1-cosx
ANTONII [103]
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).

 </span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).

 </span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.

 </span>
<span>I hope this helps! </span>
8 0
3 years ago
The scale factor from a small triangle ABC to a large triangle XYZ is 5. How many times larger will the perimeter of triangle XY
Ierofanga [76]

Answer:

Answer below :)

Step-by-step explanation:

Hi there!

Question 4 - the answer will be 5. Since the scale factor is 5, we would (hypothetically) multiply the area by 5 to get the new area of XYZ, so area XYZ is 5 times the area of ABC.

Question 5 - A.

First we multiply 45 by 12 to find the amount in inches. This is 540. Now, we divide that by 6 to get 90. This is our scale factor in inches, but the answers only show the scale in feet, so we have to convert. Divide 90 by 12 to get 7.5.

I hope this helps!

4 0
2 years ago
HELP PLEASE IM ALMOST DONE I WILL MARK BRAINLIEST
gulaghasi [49]

Answer:

y = 94

x = 86

Step-by-step explanation:

brainliest plz

7 0
3 years ago
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