It would make 5 complete frames, and about 8/10 of another frame.
108 / 18.375 = 5.8&*)&^&%*$*
I used a calculator.
You could keep adding 18 and 3/8 over and over again until you get right under 108 if you're good at math like me, but most people would have to add 18 and 3/8 separately.
Thanks, and if you liked my answer, please consider giving me the brainliest answer, because I need 5 of them to get to the next level.
Answer:
The temperature of the weather station was 3 degrees Celcius an hour earlier.
Step-by-step explanation:
We can say that the weather an hour ago should be represented with the variable - x.
From the problem, we know that the temperature of the station falls at a rate of -3 degrees per hour. This means that for every hour, the temperature of the place will go down by about 3 degrees Celsius.
If the temperature of the weather station is currently 0 degrees Celsius, to find its temperature an hour earlier, it means that we will need to add 3 degrees to its current temperature, because that is what must have lost in one hour.
i.e x = 0 + 3 = 3 degrees Celcius.
This means that the temperature of the weather station was 3 degrees Celcius an hour earlier.
Answer:
6.7
Step-by-step explanation:
60$-37.45=22.55
22.55/3.35=6.731
Which rounds to 6.7
Answer:
m GHI = 82°
Step-by-step explanation:
59+39=98
180-98=82 <==== answer
180 is the total amount of degree
You know 1 is not a root because the sum of the coeffcients of the equation is 14, not zero.
It is fairly easy to try 3 by synthetic division (see attachment), which tells you that 3 is a root and the remaining quadratic factor is x²-3x-5. The quadratic formula tells you the roots of that factor are
... x = (-b±√(b²-4ac))/(2a) = (3±√29)/2
The appropriate choices are
... C. (3-√29)/2
... D. (3+√29)/2
... F. 3
_____
The quadratic formula tells you the solution to
... ax²+bx+c=0
is x = (-b±√(b²-4ac))/(2a)
We have a=1, b=-3, c=-5.
