Answer: 8,000,000
Step-by-step explanation:
Given the following :
EOQ = 4000
Ordering cost (S) = $25
Carrying cost = 25% of unit cost
Cost per load = $100
Let annual demand = D
EOQ = sqrt[ ( 2 * S * D) / H]
Holding cost = H = 0.25 × $100 = $25
Hence,
4000 = sqrt[ ( 2 * 25 * D) / 25]
4000 = (50D /25)^1/2
Square both sides
4000² = 50D / 25
16,000,000 × 25 = 50D
400000000 = 50D
D = 400000000 / 50
D = 8,000,000
Hence, annual demand = 8,000,000
cos(2 x) + 2 = sin(x)
Solve for x over the real numbers:
sin(x) - cos(2 x) = 2
Transform sin(x) - cos(2 x) into a polynomial with respect to sin(x) using cos(2 x) = 1 - 2 sin^2(x):
-1 + sin(x) + 2 sin^2(x) = 2
Divide both sides by 2:
-1/2 + sin(x)/2 + sin^2(x) = 1
Add 1/2 to both sides:
sin(x)/2 + sin^2(x) = 3/2
Add 1/16 to both sides:
1/16 + sin(x)/2 + sin^2(x) = 25/16
Write the left hand side as a square:
(sin(x) + 1/4)^2 = 25/16
Take the square root of both sides:
sin(x) + 1/4 = 5/4 or sin(x) + 1/4 = -5/4
Subtract 1/4 from both sides:
sin(x) = 1 or sin(x) + 1/4 = -5/4
Take the inverse sine of both sides:
x = 2 π n + π/2 for n element Z
or sin(x) + 1/4 = -5/4
Subtract 1/4 from both sides:
x = 2 π n + π/2 for n element Z
or sin(x) = -3/2
sin(x) = -3/2 has no solution since for all x element R, -1<=sin(x)<=1 and -3/2<-1:
Answer: |
| x = 2 π n + π/2 for n element Z
<u>x = 1/2 (4 π n + π)</u> n element Z
Paralell lines have the same slope
perpendicular lines have slopes that multiply to get -1
neither is niegher
so
y=mx+b
m=slope
x=y+2
minus 2
x-2=y
y=x-2
y=1x-2
slope is 1
y=x+3
y=1x+3
1=1
they are paralell
Answer:
-4/5.
Step-by-step explanation:
The 2 marked points are (-3, 2) and (2, -2)
So the slope = (-2-2)/(2- -3)
= -4/5.
Year 1= 60 x .5 =30
Year 2=30 x .5 =15
Year 3=15 x .5 =7.5
Year 4=7.5 x .5 =3.75
The answer is 3.75