Question

I really need this answr tonight please HELP!!! Use limits to find the area between the graph of the function and the x axis given by the definite integral. ∫_1^5▒(x^2-x+1)dx

Answer 1

Step-by-step explanation:

$\int_1^5( {x}^{2} - x + 1)dx$

$( { \frac{ {x}^{3} }{3}} - \frac{ {x}^{2} }{2} + x)_1^5$

$( \frac{125}{3} - \frac{25}{2} + 5) - ( \frac{1}{3} - \frac{1}{2} + 1)$

$( \frac{124}{3} - 8)$

$(33.3)$

Answer 2

Answer:

34.33

Step-by-step explanation:

x³/3-x²/2 +x

this is because it is integration you are doing.

so u add 1 to the power And divide it by the answer you get for the power.

5³/3-5²/2+5-1³/3-1²/2+1

this is due to the fact that it is a definite integral so u have to substitute the lower and upper limits into the Integral function and subtract

=34.33