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Evgesh-ka [11]
3 years ago
7

Your class is learning to tie knots. Each student needs a piece of rope that is

Mathematics
1 answer:
Korvikt [17]3 years ago
8 0

Answer:

6 yards of rope

Step-by-step explanation:

1 yard = 3 feet

3/8*16= 6 yards

hope this was helpful

plz mark Brainliest

im trying to rank up ;p

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Katie bought 2 soda at the baseball game if each soda cost $2.80 and she paid with a twenty dollar bill how much change should s
gladu [14]

Answer:

$15.40

Step-by-step explanation:

2.80*2=5.60

20.00-5.60=15.40

4 0
3 years ago
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Express it in slope-intercept form.
GREYUIT [131]

Answer:

  y = (2/3)x -1

Step-by-step explanation:

The line crosses the y-axis at -1, so that is the y-intercept.

From that point. the next grid intersection is 3 units to the right and 2 units up, so the slope is ...

  m = rise/run = 2/3

The slope-intercept form of the equation of a line is ...

  y = mx +b . . . . . where m is the slope (2/3) and b is the y-intercept (-1)

Your line has equation ...

  y = (2/3)x -1

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3 years ago
Student scores on exams given by a certain instructor have mean 74 and standard deviation 14. This instructor is about to give t
Lapatulllka [165]

Answer:

P(\bar X >80)=P(Z>2.143)=1-P(z

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable that represent the Student scores on exams given by a certain instructor, we know that X have the following distribution:

X \sim N(\mu=74, \sigma=14)

The sampling distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

The deduction is explained below we have this:

E(\bar X)= E(\sum_{i=1}^{n}\frac{x_i}{n})= \sum_{i=1}^n \frac{E(x_i)}{n}= \frac{n\mu}{n}=\mu

Var(\bar X)=Var(\sum_{i=1}^{n}\frac{x_i}{n})= \frac{1}{n^2}\sum_{i=1}^n Var(x_i)

Since the variance for each individual observation is Var(x_i)=\sigma^2 then:

Var(\bar X)=\frac{n \sigma^2}{n^2}=\frac{\sigma}{n}

And then for this special case:

\bar X \sim N(74,\frac{14}{\sqrt{25}}=2.8)

We are interested on this probability:

P(\bar X >80)

And we have already found the probability distribution for the sample mean on part a. So on this case we can use the z score formula given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

Applying this we have the following result:

P(\bar X >80)=P(Z>\frac{80-74}{\frac{14}{\sqrt{25}}})=P(Z>2.143)

And using the normal standard distribution, Excel or a calculator we find this:

P(Z>2.143)=1-P(z

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4 years ago
which of tthe following fucngions describes the average expense fir a player played, in terms of x, the number of games played?
Firdavs [7]
And we are waiting to see the functions listed?
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4 years ago
Ricky spends $103. 19 in additional interest and charges on monthly payments as the result of a prior bankruptcy. If Ricky had b
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Answer:

C. 1,315.06

Step-by-step explanation:

................

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