Ask question

Ask question

All categories

tekilochka [14]

2 years ago

13

Jaffrey was offered a job at $950 per month with a $22 increase every month for the first year. How much money can he make in th

e first year

1 answer:

IrinaVladis [17]2 years ago

8 0

Answer:

11,664 is the possibility answer to your question

You might be interested in

What's the percent of 0.235 and fraction of 0.235?

BartSMP [9]

It is 47/200 I think.

4 0

3 years ago

What is x when the equation is 5|2x+3|=45?

storchak [24]

1.)divide by 5 on each side to obtain
Abs(2x+3)=45
2x+3=45 or 2x+3=-45
2x=42 or 2x=-48
x=21 or x=-24

6 0

3 years ago

Read 2 more answers

Given two independent random samples with the following results: n1=8x‾1=186s1=33 n2=7x‾2=171s2=23 Use this data to find the 90%

KonstantinChe [14]

Answer:

The point of estimate for the true difference would be:

$186-171= 15$

And the confidence interval is given by:

$(186-171) -1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= -10.753$

$(186-171) +1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= 40.753$

Step-by-step explanation:

For this case we have the following info given:

$\bar X_1 = 186$ the sample mean for the first sample

$\bar X_2 = 171$ the sample mean for the second sample

$s_1 =33$ the sample deviation for the first sample

$s_2 =23$ the sample deviation for the second sample

$n_1 = 8$ the sample size for the first group

$n_2 = 7$ the sample size for the second group

The confidence interval for the true difference is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

We can find the degrees of freedom are given:

$df = n_1 +n_2 -2 =8+7-2= 13$

The confidence level is given by 90% so then the significance would be $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ we can find the critical value with the degrees of freedom given and we got:

$t_{\alpha/2}= \pm 1.77$

The point of estimate for the true difference would be:

$186-171= 15$

And replacing into the formula for the confidence interval we got:

$(186-171) -1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= -10.753$

$(186-171) +1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= 40.753$

5 0

3 years ago

All real numbers y greater than or equal to 12?

serious [3.7K]

It is very important to read the question very minutely and then it would be easy to reach a logically correct solution. It is important to note that "y" is greater than or equal to 12 and y is considered as all real numbers. Then we can mathematically represent this situation as
y <span>≥ 12</span>

7 0

3 years ago

-3 = t/-15. solve for t.

Oliga [24]

Answer:

t=45

Step-by-step explanation:

-3=t/-15 step one multiply both sides by denominator

-3 x -15 = 45

3 0

3 years ago

Read 2 more answers