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3 years ago

10

One of Gemma's 5 friends is going to upgrade to a newer device soon. The average cost of their devices will then increase to $66

3 from the previous $657. How much more expensive than the older one is this newer device?

1 answer:

larisa [96]3 years ago

8 0

Old value of 5 devices = 657
New value of 5 devices = 663

Increment cost of 5 devices
663 - 657
6

Therefore the increment for one device
6 / 5
1.2

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Answer:

The train need to leave Portland at 03:27 am

Step-by-step explanation:

step 1

Find out how long it takes the train to travel from Portland, Oregon, to Los Angeles, California

Remember that

The speed is equal to divide the distance by the time

so

The time is equal to divide the distance by the speed

Let

s ---> the speed in miles per hour

d ---> the distance in miles

t ---> the time in hours

$t=\frac{d}{s}$

we have

$d=963\ mi$

$s=60\ mi/h$

substitute

$t=\frac{963}{60}=16.05\ hours$

step 2

Adds 30 minutes (time it takes to get from the train station to her aunt's house)

Remember that

$30\ minutes=0.50\ hours$

$16.05+0.50=16.55\ hours$

Convert to minutes

$16.55\ h=16.55(60)\ min=993\ min$

step 3

Remember that

$8 p.m=20:00\ hrs$

Convert to minutes

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$1,200-993=207\ min$

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$207\ min=207/60=3.45\ hours$

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so

$3\ h+27\ min$

$00:00 + 03:27=03:27\ am$

therefore

The train need to leave Portland at 03:27 am

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a) The halfway number is $\frac{-4.5}{10}$ .

b) The ascending order is $\frac{-1}{2}$ , $\frac{-4.5}{10}$ and $\frac{-2}{5}$ .

<u>Step-by-step explanation:</u>

a)Halfway number is otherwise Middle number.

The halfway number of two numbers = $\frac{sum of two numbers}{2}$ .

The halfway for $\frac{-2}{5}$ and $\frac{-2}{5}$ = $\frac{\frac{-2}{5}+ (\frac{-1}{2})}{2}$ .

= $\frac{-2}{5}+ (\frac{-1}{2})$ .

= $\frac{-4-5}{10}$ .

= $\frac{-9}{10}$ .

∴Halfway = $\frac{\frac{-9}{10} }{2}$ .

= $\frac{-4.5}{10}$

The halfway for $\frac{-2}{5}$ and $\frac{-1}{2}$ = $\frac{-4.5}{10}$ .

b) The ascending order is $\frac{-1}{2}$ , $\frac{-4.5}{10}$ and $\frac{-2}{5}$ .

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