Start from Start Here square, the pointer to the next question to resolve is given by the solution to the equation in the current square
The values of the Maze are as follows;
- x = 10
- x = 8
- x = -9
- x = 5
- x = 11
- x = 3
- x = -5
- x = 9
- x = 7
- x = -7
Reason:
The solutions are;
10·x + 15 = 12·x - 5 by alternate interior angles theorem
6·x + 6 = 5·x + 14 by alternate exterior angles theorem
x + 109 = 100 by corresponding angles theorem
11·x + 5 + 120° = 180° by same side interior angles theorem
11·x - 1 = 10·x + 10 by corresponding angles theorem
35·x + 5 = 110 by corresponding angles theorem
x + 85 + x + 105 = 180 by same side interior angles theorem
7·x - 3 + 12·x + 12 = 180° by same side interior angles theorem
19·x - 3 = 130 by alternate interior angles theorem
x + 67 = 60 by alternate interior angles theorem
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Answer:
(t,s)
Step-by-step explanation:
this point has the x value t and the y value s that is missing.
Try out this website or search "surface area of a triangular prism" in Google
http://www.ck12.org/geometry/Surface-Area-of-Triangular-Prisms/lesson/Surface-Area-of-Triangular-Pri...
Solving a system of linear equations, we conclude that the measure of side Z is 2√13
<h3>How to find the measure of side Z?</h3>
Remember the Pythagorean theorem. It says that the square of the hypotenuse is equal to the sum of the squares of the legs.
In the image, we can identify 3 right triangles, and with the Pythagorean theorem, we can write a system of 3 equations.
x^2 = y^2 + 4^2
z^2 = y^2 + 9^2
(4 + 9)^2 = z^2 + x^2
We want to solve that for z.
Now, the second equation can be rewritten to:
y^2 = z^2 - 9^2
Now let's replace the first equation into the third one, so we get:
(4 + 9)^2 = z^2 + (y^2 + 4^2)
Now we can replace y^2 by z^2 - 9^2
(4 + 9)^2 = z^2 + ((z^2 - 9^2) + 4^2)
Now we can solve this:
(13)^2 = z^2 + z^2 - 9^2 + 4^2
(13)^2 + 9^2 - 4^2 = 2*z^2
104/2 = z^2
52 = z^2
√52 = z
√(4*13) = z
√4*√13 = z
2√13 = z
We conclude that the measure of side Z is 2√13
If you want to learn more about systems of equations:
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