Answer:
vertex = (- 1, 3 )
Step-by-step explanation:
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
= -
y = 2x² + 4x + 5 ← is in standard form
with a = 2, b = 4, then
= -
= - 1
Substitute x = - 1 into the equation for corresponding value of y, that is
y = 2(- 1)² + 4(- 1) + 5 = 2 - 4 + 5 = 3
vertex = (- 1, 3 )
Under the given transformation, the Jacobian and its determinant are
so that
where is the region
transformed into the
-
plane. The remaining integral is the twice the area of
.
Now, the integral over is
but through the given transformation, the boundary of is the set of equations,
We require that , and the last equation tells us that we would also need
. This means
and
, so that the integral over
is