Answer:
I think the question is 1,176
Answer:
(m+3) (m-8)
Step-by-step explanation:
...,...............
Answer:
18+45x
Step-by-step explanation:
<span>Acceleration of a passenger is centripetal acceleration, since the Ferris wheel is assumed at uniform speed:
a = omega^2*r
omega and r in terms of given data:
omega = 2*Pi/T
r = d/2
Thus:
a = 2*Pi^2*d/T^2
What forces cause this acceleration for the passenger, at either top or bottom?
At top (acceleration is downward):
Weight (m*g): downward
Normal force (Ntop): upward
Thus Newton's 2nd law reads:
m*g - Ntop = m*a
At top (acceleration is upward):
Weight (m*g): downward
Normal force (Nbottom): upward
Thus Newton's 2nd law reads:
Nbottom - m*g = m*a
Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame:
Ntop = m*(g - a)
Nbottom = m*(g + a)
Substitute a:
Ntop = m*(g - 2*Pi^2*d/T^2)
Nbottom = m*(g + 2*Pi^2*d/T^2)
We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground):
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g)
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g)
Simplify:
Ntop/(m*g) = 1 - 2*Pi^2*d/(g*T^2)
Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2)
Data:
d:=22 m; T:=12.5 sec; g:=9.8 N/kg;
Results:
Ntop/(m*g) = 71.64%...she feels "light"
Nbottom/(m*g) = 128.4%...she feels "heavy"</span>
9514 1404 393
Answer:
3) x = 9
4) x = 3
Step-by-step explanation:
3) The two short segments are indicated as having a sum equal to the long segment.
(x +2) +(-5 +x) = 15
2x = 18 . . . . . . . . . . . . add 3
x = 9 . . . . . . . . . divide by 2
(This makes the segments be 9+2 = 11 and -5+9 = 4, which total 15.)
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4) Same deal.
3x +3 = 4x
3 = x . . . . . . . . subtract 3x
(This makes the segments be 3(3) = 9 and 4(3) = 12, where 9+3=12.)
