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3 years ago

Find the coordinates of the midpoint of the segment given its endpoints.

Mathematics

1 answer:

Vesna [10]3 years ago

6 0

Answer:

(2, 2 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ $\frac{1}{2}$ (x₁ + x₂ ) , $\frac{1}{2}$ (y₁ + y₂ ) ]

Here (x₁, y₁ ) = (A(5, 8) and (x₂, y₂ ) = B(- 1, - 4) , thus

midpoint = [ $\frac{1}{2}$ (5 - 1), $\frac{1}{2}$ (8 - 4 ) ] = (2, 2 )

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2x+y=-6<br><br>what are the x and y intercepts

Deffense [45]

Answer:

Step-by-step explanation:

y intercept

To find the y intercept, make x = 0

2(0) + y = - 6 zero times anything is 0

0 + y = -6

The y intercept is (0,-6)

x intercept

The x intercept happens when y = 0

2x + 0 = -6 zero added to anything = whatever you started with.

2x = - 6 Divide by 2

2x/2 = -6/2 Do the division

x = - 3

The x intercept = (-3,0)

5 0

3 years ago

Please help! im very confused.

Vitek1552 [10]

Answer:

if am right it's 90

Step-by-step explanation:

8 0

2 years ago

Sarah used 2.5 cups of cheese in a dish that serves 10 people. Amyn used 1.6 cups of cheese in a dish that serves 8 people.

Drupady [299]

Is D
Explanation : you have to divide the amounts too see how many cheese for one person and then you subtract them and you get you answer that will be like this
2.5 divided by 10 = 0.25
1.6 divided by 8 = 0.2
0.25 - 0.2 = 0.05

5 0

2 years ago

The function f(x) = 5One-fifth is reflected over the y-axis. Which equations represent the reflected function? Select two option

postnew [5]

Answer:

The equations that represent the reflected function are

$f(x)=5(\frac{1}{5})^{-x}$

$f(x)=5(5)^{x}$

Step-by-step explanation:

The correct question in the attached figure

we have the function

$f(x)=5(\frac{1}{5})^{x}$

we know that

A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.

therefore

$f(−x) = f(x).$

The reflection of the given function across the y-axis will be equal to

(Remember interchanges positive x-values with negative x-values)

$f(x)=5(\frac{1}{5})^{-x}$

An equivalent form will be

$f(x)=5(\frac{1}{5})^{(-1)(x)}=5[(\frac{1}{5})^{-1})]^{x}=5(5)^{x}$

therefore

The equations that represent the reflected function are

$f(x)=5(\frac{1}{5})^{-x}$

$f(x)=5(5)^{x}$

9 0

2 years ago

Read 2 more answers

A cone-shaped paper drinking cup is to be made to hold 27 cm of water. Find the height h and radius r of the cup that will use t

andreyandreev [35.5K]

Answer:

r = 2.632 cm
h = 3.722 cm

Step-by-step explanation:

The formula for the volume of a cone of radius r and height h is ...

V = (1/3)πr²h

Then r² can be found in terms of h and V as ...

r² = 3V/(πh)

The lateral surface area of the cone is ...

A = (1/2)(2πr)√(r² +h²) = πr√(r² +h²)

The square of the area is ...

T = A² = π²r²(r² +h²)

Substituting for r² using the expression above, we have ...

T = π²(3V/(πh))((3V/(πh) +h²) = 9V²/h² +3πVh

We want to find the minimum, which we can do by setting the derivative to zero.

dT/dh = -18V²/h³ +3πV

This will be zero when ...

3πV = 18V²/h³

h³ = 6V/π . . . . . multiply by h³/(3πV)

For V = 27 cm³, the value of h that minimizes paper area is ...

h = 3∛(6/π) ≈ 3.7221029

The corresponding value of r is ...

r = √(3V/(πh)) = 9/√(π·h) ≈ 2.6319242

The optimal radius is 2.632 cm; the optimal height is 3.722 cm.

_____

The second derivative test applied to T finds that T is always concave upward, so the value we found is a minimum.

Interestingly, the ratio of h to r is √2.

8 0

3 years ago