Question

Please find the answer to this function! F(2)= 6x^4-10x^3+40x-50

Answer 1

Answer-

$f(2)= 6x^4-10x^3+40x-50=46$

Solution-

The given function is,

$\Rightarrow f(x)= 6x^4-10x^3+40x-50$

Now, we have to find the value of f(x) at x=2 i.e f(2), so putting x as 2 in the given function,

$\Rightarrow f(2)= 6(2)^4-10(2)^3+40(2)-50$

$\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50$

$\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50$

$\Rightarrow f(2)= 96-80+80-50$

$\Rightarrow f(2)= 96-50$

$\Rightarrow f(2)= 46$

Therefore, f(2) was found to be 46.