R is proportional to the length of the wire:
R ∝ length
R is also proportional to the inverse square of the diameter:
R ∝ 1/diameter²
The resistance of a wire 2700ft long with a diameter of 0.26in is 9850Ω. Now let's change the shape of the wire, adding and subtracting material as we go along, such that the wire is now 2800ft and has a diameter of 0.1in.
Calculate the scale factor due to the changed length:
k₁ = 2800/2700 = 1.037
Scale factor due to changed diameter:
k₂ = 1/(0.1/0.26)² = 6.76
Multiply the original resistance by these factors to get the new resistance:
R = R₀k₁k₂
R₀ = 9850Ω, k₁ = 1.037, k₂ = 6.76
R = 9850(1.037)(6.76)
R = 69049.682Ω
Round to the nearest hundredth:
R = 69049.68Ω
Answer:
I feel like to demonstrate you would use an elastic band as the material. You obviously have to put force in order to see how far it stretches. From this you can also find about its resistance and durability
Also you have to make sure the distance between the two hands are equal as you want an accurate result.
very interesting and amazing question u had asked but i get it...
Answer
W = Force × Displacement
- but in above case force is exerted on the men as the weight of the child × gravitational pull of earth (9.8 m/s^2) but the displacement or movement is ZERO
- there for W= F×0 =0
- so even after carrying child for 2 hours work done by the men will be zero
<u>More</u><u> </u><u>examples</u>
- a person standing straight and lifting weight
- a person carry some weight and walk in a circular path and came back to its original position.........in this case also Displacement will be zero
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hope it helped u buddy
Hey there Evan!
Let's remember, these are (light waves). So, we you learn about waves, you would remember that when light does reach an end, they will most likely just (bounce back). That's all it would actually do.
I Hope this helps you!