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LenaWriter [7]
4 years ago
14

a rectangle has a width w and it's length is 3w-2. if the area is 65ft^2, find the length and width of the rectangle. ​

Mathematics
1 answer:
charle [14.2K]4 years ago
8 0

Answer:

Width = 5

Length = 13

Step-by-step explanation:

Area of a rectangle:

=> L x W = Area

After knowing this, we could find the factors of 65

=> 65 = 5 x 13, 1 x 65

So, the only way is 5 x 13.

So, Width = 5

     Length = 13

Let's check whether our answer is correct.

=> (3w - 2) * w  = 65

=> (3 (5) - 2) * 5 = 65

=> (15 - 2) * 5 = 65

=> 13 * 5 = 65

=> 65 = 65

So, our answer is correct.

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4 years ago
Under average driving conditions, the life lengths of automobile tires of a certain brand are found to follow an exponential dis
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Answer:

a) P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

b) P(X>30000|X>15000)=P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "life lengths of automobile tires of a certain brand" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{30000})

The cumulative distribution function is given by:

F(X) = 1- e^{-\frac{x}{\mu}}

Part a

We want to find this probability:

P(X>30000) and for this case we can use the cumulative distribution function to find it like this:

P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

Part b

For this case w want to find this probability

P(X>30000|X>15000)

We have an important property on the exponential distribution called "Memoryless" property and says this:

P(X>a+t| X>t)=P(X>a)  

On this case if we use this property we have this:P(X>30000|X>15000)=P(X>15000+15000|X>15000)=P(X>15000)

We can use the definition of the density function and find this probability:

P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

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Answer:

Step-by-step explanation:

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