From the set (33, 15, 12), use substitution to determine which value of x makes the equation true.

Last question and then I’ll take care of the rest on my own ^^^^

Bond [772]

Answer:

(c) 5/2

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

(a^b)/(a^c) = a^(b-c)

a^-b = 1/a^b

__

Using these rules, we can simplify the expression as follows:

(5^-3)(2^2)(5^6)/((2^3)(5^2)) = (5^(-3+6-2))(2^(2-3)) = (5^1)(2^-1)

= 5/2

6 0

3 years ago

(ASAP PICTURE ADDED) What is the simplified form of the following expression?

bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

$7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)$

WE need to simplify this equation.

Solve the parenthesis of each term.

$=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right$

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation: $=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)$

Adding like terms we get:

$=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\$

$(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)$

So, option c is correct

5 0

3 years ago

Read 2 more answers

The length of the rectangle is 7/(x-4) feet, while its width is 5/x feet. Find its perimeter. Please help asap!!!!! :(

damaskus [11]

The perimeter would be (24x - 40)/(x^2 - 4x).

In order to find this, first double the length and width as you would to find any perimeter.

7/(x - 4) * 2 = 14/(x - 4)

5/x * 2 = 10/x

Now to add those together, we need to give them common denominators. In order to do that with the first one, we need to multiply by x/x

14/(x - 14) * x/x = 14x/(x^2 - 14x)

Then we can do the same with the second part by multiplying by (x - 4)/(x - 4)

10/x * (x - 4)/(x - 4) = (10x - 40)/(x^2 - 14x)

Now we can add the two together

14x/(x^2 - 14x) + (10x - 40)/(x^2 - 14x) = (24x - 40)/(x^2 - 14x)

3 0

3 years ago

State the equation of the line described.

nikdorinn [45]

Answer:

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes. This means that when you multiply the slopes of the perpendicular lines, its product = -1.

Given the linear equation, y = -9x - 1, and the point, (-3, 7):

Since the slope of the given linear equation is: m1 = -9, then it means that the slope of the other line (m2) = 1/9:

m1 × m2 = -1

-9 × 1/9 = -1

Next, we need to find the y-intercept of the other line. The y-intercept is the point on the line where it crosses the y-axis, and has coordinates (0, <em>b</em>). It is also the value of the y-coordinate when its corresponding x-coordinate = 0.

Using the given point, (-3, 7), and the slope of the other line, m2 = 1/9:

We need to substitute these values into the slope-intercept form, y = mx + b, to solve for the y-intercept, (b):

y = mx + b

7 = 1/9(-3) + b

7 = -1/3 + b

Add 1/3 to both sides of the equation to solve for b:

7 + 1/3 = 1/3 -1/3 + b

22/3 = b

Therefore, the y-intercept (b) = 22/3.

The linear equation of the other line is: y = 1/9x + 22/3

4 0

2 years ago

If D=20 miles when T=15 minutes, write a proportion to find D for T=20 minutes

Igoryamba

D/20=20/15

d=400/15

d=80/3

d=26 2/3 miles

8 0

3 years ago