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katrin2010 [14]
3 years ago
10

This question refers to a standard deck of playing cards. If you are unfamiliar with playing cards, there is an explanation in P

robability of an event' section under the heading Standard playing cards. A five-card hand is just a subset of 5 cards from a deck of 52 cards. How many different five-card hands are there from a standard deck of 52 playing cards? How many five-card hands have exactly two hearts? How many five-card hands are made entirely of hearts and diamonds? How many five-card hands have four cards of the same rank? A full house" is a five-card hand that has two cards of the same rank and three cards of the same rank. For example, (queen of hearts, queen of spades, 8 of diamonds, 8 of spades, 8 of clubs). How many five-card hands contain a full house? How many five-card hands do not have any two cards of the same rank?
Computers and Technology
2 answers:
Karolina [17]3 years ago
5 0

Answer:

Number of ways = 2595960

P(two hearts) = 0.003 %

P(hearts and diamonds) = 63.73 %

P(4 same rank) = 0.024 %

P(full house) = 0.144 %

P(No same rank) = 50.7 %

Explanation:

How many different five-card hands are there from a standard deck of 52 playing cards?

There are total 52 cards out of which we have to select 5 cards

Number of ways = 52C5

Number of ways = 2595960

There are 2595960 different ways of dealing five-card hands

How many five-card hands have exactly two hearts?

There are total 13 hearts out of which we have to select two hearts

P(two hearts) = 13C2/52C5

P(two hearts) = 78/2598960

P(two hearts) = 0.003 %

How many five-card hands are made entirely of hearts and diamonds?

P(hearts and diamonds) = 13C5*13C5/52C5

P(hearts and diamonds) = 1287*1287/2598960

P(hearts and diamonds) = 1656369/2598960

P(hearts and diamonds) = 63.73 %

How many five-card hands have four cards of the same rank?

P(4 same rank) = 13C1*12C1*4C1/5C2

P(4 same rank) = 13*12*4/2598960

P(4 same rank) = 624/2598960

P(4 same rank) = 0.024 %

How many five-card hands contain a full house?

P(full house) = 13C2*2C1*4C3*4C2/5C2

P(full house) = 78*2*4*6/2598960

P(full house) = 3744/2598960

P(full house) = 0.144 %

How many five-card hands do not have any two cards of the same rank?

P(No same rank) = 13C5*4C1*4C1*4C1*4C1*4C1/5C2

P(No same rank) = 1287*4*4*4*4*4/2598960

P(No same rank) = 1317888/2598960

P(No same rank) = 50.7 %

Norma-Jean [14]3 years ago
4 0

Answer:

Explanation:

Number of ways to select 10 girls in 35C₁₀

Number of ways to select 10 boys in 35C₁₀

Total Number of ways to select is 35C₁₀ x 35C₁₀

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// Program written in C++

// Comments are used to explain some lines

#include <iostream>

#include <iomanip>

using namespace std;

// Functions

void getData(double *, int);

void selectionSort(double *, int);

double getAverage(double *, int);

void displayData(double *, int, double);

int main() //Main Method

{

double *ToTest, // To dynamically allocate an array

Average; // To hold the average of the scores

int Scores; // To hold number of scores

// Get number of scores

cout << "Number of average to find? ";

cin >> Scores;

// Allocate an array to number of scores

ToTest = new double[Scores];

getData(ToTest, Scores);

selectionSort(ToTest, Scores);

Average = getAverage(ToTest, Scores);

printData(ToTest, Scores, Average);

return 0;

}

//Get Data

void getData(double *ToTest, int Scores)

{

cout << "Enter each scores.\n";

for (int i = 0; i < Scores; i++)

{

do

{

cout << "Score #" << (i + 1) << ": ";

cin >> *(ToTest + i);

if (*(ToTest + i) < 0)

{

cout << "Scores must be greater than 0.\n"

<< "Re-enter ";

}

} while (*(Test + i) < 0);

}

}

// Selection Sort

void selectionSort(double *ToTest, int Scores)

{

int startscan, minIndex;

double minValue;

for (startscan = 0; startscan < (Scores - 1); startscan++)

{

minIndex = startscan;

minValue = *(ToTest + startscan);

for (int i = startscan + 1; i < Scores; i++)

{

if (*(ToTest + i) < minValue)

{

minValue = *(Test + i);

minIndex = i;

}

}

*(ToTest + minIndex) = *(ToTest + startscan);

*(ToTest + startscan) = minValue;

}

}

// Calculate Average

double getAverage(double *ToTest, int Scores)

{

double Total;

for (int i = 0; i < Scores; i++)

{

Total += *(ToTest + i);

}

return Total / Scores;

}

// Print Data

void printData(double *ToTest, int Scores, double Avg)

{

cout << "\n Test scores\n";

cout << "Number of scores: " << Scores << endl;

cout << "Scores in ascending-order:\n";

for (int i = 0; i < Scores; i++)

{

cout << "#" << (i + 1) << ": " << *(ToTest + i) << endl;

}

cout << fixed << showpoint << setprecision(2);

cout << "Average score: " << Avg << endl;

}

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