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sergiy2304 [10]
3 years ago
15

K divided by 11 is 7 equations

Mathematics
2 answers:
Monica [59]3 years ago
5 0
K divide by 11 is 7 is 77
maria [59]3 years ago
4 0

Answer:

k=77

Step-by-step explanation:

k/11=7

(k/11)*11=7*11

k=77

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Anyone know the answers 11 through 20?
Evgen [1.6K]

Step-by-step explanation:

11) x^5

12) 5x^2

13) x+21

14) 2x-8

15) 3^3

=3*3*3

=27

16)2^5

=2*2*2*2*2

=32

17) 5^4

=5*5*5*5

=625

18)2 times a number p squared

19)3 times a number m fifth power

20)the addition of half a number and 2

5 0
3 years ago
Neil took his family of five out to dinner at HogTastic Pit BBQ. They all ordered the buffet and drink at $12.80 each. Neil left
aliina [53]
$12.80 × 1.075 = $13.76

$13.76 × 1.15 =$15.82
5 0
3 years ago
7. Solve the equation.<br> 6(x - 2) = 36<br> 0-8<br> 04<br> 04<br> 08<br> What one
rusak2 [61]

Answer:

8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

6(x - 2) = 36

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Divide 6 on both sides:                     x - 2 = 6
  2. Add 2 on both sides:                         x = 8
6 0
3 years ago
the number of televisions owned by Matt's classmates is 1, 4, 3, 3, 2, 1, and 7. what is the mean absolute deviation for the num
erik [133]
The answer is 3
Add all numbers (21) then divide by 7 (there are seven numbers there)
So the answe is 3
8 0
3 years ago
Write a recursive formula for an, the nth term of the sequence 3, -4, -11
yKpoI14uk [10]

Answer:

, 12, 48, 192...

a. Write a recursive formula for the nth term of the sequence

Ans: a(n+1) = 4*a(n)

------------------------------

b. Write a general formula for the nth term of the sequence

a(n) = 3*4^(n-1)

--------------

c. Calculate S10 for this sequence

Geometric sequence with a(1) = 3 and r = 4

----?

Step-by-step explanation:

8 0
3 years ago
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