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Serhud [2]
3 years ago
6

Which factorization is equivalent to 4y2 − 17y + 15?

Mathematics
1 answer:
iogann1982 [59]3 years ago
8 0
I think its 4y2 im not for sure but hope it help
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If 1/2 cup of fruit cocktail contains 13g of sugar, then 1 1/4 cup of fruit cocktail contains how many grams of sugar?
Alexus [3.1K]

Answer : 32.5 g of sugar

Step-by-step explanation:

1 1/4 cup = (4+1)/4 = 5/4 cup

If 1/2 cup contains 13 g of sugar

Then 5/4 cup contains C g of sugar

C = 5/4 * 13g➗1/2 = 5*13*2g➗4 = 130g➗4 = 32.5 g of sugar

Answer : 32.5 g of sugar

<h2><em>Spymore</em></h2>
7 0
2 years ago
Which point lies on the graph of y = 2?A. (1.2)B. (1-2)C. (2, 18)D.(3, 2)
irinina [24]

A garph y=2 represents a line parallel to the x axis with the y coordinate equal to 2.

The point which lies on the y=2 graph has its y coordinate equal to 2.

In the given options, (3,2) is the coordinate with the y coordinate equal to 2.

Hence, (3,2) lies on the graph of y = 2.

Option (D) is the answer.

3 0
9 months ago
Simplify the expression
skelet666 [1.2K]
This is the expression simplified:
4 0
2 years ago
Whats the equation of a line perpendicular to y= 0.25x-7 and passes through (-6,8)
-Dominant- [34]
y - 8 = 4(x + 6)
The slope perpendicular to 1/4 or .25 is 4.
Then you would use point slope form to write the equation.
Then you could simiplify the equation to y=4x+32.
8 0
3 years ago
A school has 1800 students and 1800 light bulbs, each with a pull cord and all in a row. All the lights start out off. The first
Gnom [1K]

<u>Solution-</u>

A school has 1800 students and 1800 light bulbs, each with a pull cord and all in a row.

As all the lights start out off, in the first pass all bulbs will be turned on.

In the second pass all the multiples of 2 will be off and rest will be turned on.

In the third pass all the multiples of 3 will be off, but the common multiple of 2 and 3 will be on along with the rest. i.e all the multiples of 6 will be turned on along with the rest.

In the fourth pass 4th light bulb will be turned on and so does all the multiples of 4.

But, in the sixth pass the 6th light bulb will be turned off as it was on after the third pass.

This pattern can observed that when a number has odd number of factors then only it can stay on till the last pass.

1 = 1

2 = 1, 2

3 = 1, 3

<u>4 = 1, 2, 4</u>

5 = 1, 5

6 = 1, 2, 3, 6

7 = 1, 7

8 = 1, 2, 4, 8

9 = 1, 3, 9

10 = 1, 2, 5, 10

11 = 1, 11

12 = 1, 2, 3, 4, 6, 12

13 = 1, 13

14 = 1, 2, 7, 14

15 = 1, 3, 5, 15

16 = 1, 2, 4, 8, 16

so on.....

The numbers who have odd number of factors are the perfect squares.

So calculating the number of perfect squares upto 1800 will give the number of light bulbs that will stay on.

As,  \sqrt{1800} =42.42  , so 42 perfect squared numbers are there which are less than 1800.

∴ 42 light bulbs will end up in the on position. And there position is given in the attached table.

7 0
2 years ago
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